Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
1000 square feet.
Step-by-step explanation:
to find the area, you multiply the length by the width
40*25=1000
Answer:
3x - 8
Step-by-step explanation:
To find f(x + 1) substitute x = x + 1 into f(x)
f(x + 1) = 3(x + 1) - 7 = 3x + 3 - 7 = 3x - 4
Similarly
f(1) = 3(1) - 7 = 3 - 7 = - 4
Hence
f(x + 1) + f(1) = 3x - 4 - 4 = 3x - 8
Answer:
x = 25
Step-by-step explanation:
Given
x - 5 = 20 ( isolate x by adding 5 to both sides )
x = 25
