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topjm [15]
3 years ago
10

A small fair charges an admission fee for children and adults. The cost for admission is $3 per adult and $2 per child. On a cer

tain day, total admission fees were $900, and 350 people attended the fair. How many children attended the fair that day?
Mathematics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

150 children attended the fair that day

Step-by-step explanation:

Let n represents the number of children attended.

Since there were 350 people attended, the number of adults is 350-n

Since the cost of admission is $3 per adult, the admission fee gained by adults is:

→ 3(350-n)  (1)

Since the cost of admission is $2 per child, the admission fee gained by children is:

→ 2n  (2)

Since the total admission fees were $900, the total of 1 and 2 must be equal to 900

→ 3(350-n) + 2n = 900

→ 1050 - 3n + 2n = 900

→ n = 150

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Y=x^2-6x+3 help write the vertex form of the equation
Artist 52 [7]

Answer:

y=(x-3)^2-6

Step-by-step explanation:

y=x^2-6x+3

This is written in the standard form of a quadratic function:

y=ax^2+bx+c

where:

  • ax² → quadratic term
  • bx → linear term
  • c → constant

You need to convert this to vertex form:

y=a(x-h)^2+k

where:

  • (h,k) → vertex

To find the vertex form, you need to find the vertex. For this, use the equation for axis of symmetry, since this line passes through the vertex:

x=-\frac{b}{2a}

Using your original equation, identify the a, b, and c terms:

a=1\\\\b=-6\\\\c=3

Insert the known values into the equation:

x=-\frac{(-6)}{2(1)}

Simplify. Two negatives make a positive:

x=\frac{6}{2} =3

X is equal to 3 (3,y). Insert the value of x into the standard form equation and solve for y:

y=3^2-6(3)+3

Simplify using PEMDAS:

y=9-18+3\\\\y=-9+3\\\\y=-6

The value of y is -6 (3,-6). Insert these values into the vertex form:

(3_{h},-6_{k})\\\\y=a(x-3)^2+(-6)

Insert the value of a and simplify:

y=(x-3)^2-6

:Done

6 0
3 years ago
Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applie
Y_Kistochka [10]

Answer:

The coordinates of T' will be T'(13,-1)

Step-by-step explanation:

step 1

Find the rule of the translation

take any point of rectangle JKLM (pre-image)

The coordinate of point k(-3,2)

The coordinate of point k'(4,7)

so

The rule of the transformation

k(-3,2) -----> k'(4,7)

is equal to

(x,y) ------> (x+7,y+5)

That means ----> the translation is 7 units at right and 5 units up

step 2

Apply the rule of the translation at the coordinate T of trapezoid STUV

we have

T(6,-6)

(x,y) ------> (x+7,y+5)

T(6,-6) ------> T'(6+7,-6+5)

T(6,-6) ------> T'(13,-1)

therefore

The coordinates of T' will be T'(13,-1)

6 0
3 years ago
Find the slope given (2,7) and (4,4)
8090 [49]
<h3>Answer:</h3>

m= -3/2

<h3>Step by step:</h3>

m=y1-y2/x1-x2     = 4-7/4-2      = -3/2

8 0
3 years ago
What is the distance between points (-2, 8) and (6, -2)? Round to the nearest tenth of a unit.
Mama L [17]
So you will have to find the difference between each number so 6--2=8 
and 8--2=10. So then I'm guessing you have to round 8 to 10. Sorry if this isn't all correct.
4 0
3 years ago
Can i get help please ?
wariber [46]

Answer:

D -- the last one

Step-by-step explanation:

The formula tells you what to do.

t = 3

A0 = 25

A(t) = ?

A(3)  = 25 * (1/2)^3

A(t) = 25 * 1/8

A(t) = 25/8

A(t) = 3.125

4 0
3 years ago
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