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topjm [15]
3 years ago
10

A small fair charges an admission fee for children and adults. The cost for admission is $3 per adult and $2 per child. On a cer

tain day, total admission fees were $900, and 350 people attended the fair. How many children attended the fair that day?
Mathematics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

150 children attended the fair that day

Step-by-step explanation:

Let n represents the number of children attended.

Since there were 350 people attended, the number of adults is 350-n

Since the cost of admission is $3 per adult, the admission fee gained by adults is:

→ 3(350-n)  (1)

Since the cost of admission is $2 per child, the admission fee gained by children is:

→ 2n  (2)

Since the total admission fees were $900, the total of 1 and 2 must be equal to 900

→ 3(350-n) + 2n = 900

→ 1050 - 3n + 2n = 900

→ n = 150

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3 years ago
-1/3 + (-7/4)<br> pls help
djverab [1.8K]

Answer:

  -25            

 ——— = -2.08333

    12  

Step-by-step explanation:

Step  1  :

           7

Simplify   —

           4

Equation at the end of step  1  :

       1           7

 (0 -  —) +  (0 -  —)

       3           4

Step  2  :

           1

Simplify   —

           3

Equation at the end of step  2  :

       1     -7

 (0 -  —) +  ——

       3     4

Step  3  :

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       3

     The right denominator is :       4

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

3 1 0 1

2 0 2 2

Product of all

Prime Factors  3 4 12

     Least Common Multiple:

     12

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 4

  Right_M = L.C.M / R_Deno = 3

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      -1 • 4

  ——————————————————  =   ——————

        L.C.M               12  

  R. Mult. • R. Num.      -7 • 3

  ——————————————————  =   ——————

        L.C.M               12  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

-1 • 4 + -7 • 3     -25

———————————————  =  ———

      12            12

Final result :

 -25            

 ——— = -2.08333

 12            

Processing ends successfully

plz mark me as brainliest :)

7 0
3 years ago
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Help me (question attached)
Verizon [17]

Answer:

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b. ⅖ × 3

c. ⅙ × 3

Step-by-step explanation:

i think

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Ugo [173]
I would say it’s better to buy the 36 box pens. 24\4.32=5.6 on the other hand the box of 36 is 36/5.76=6.25
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hram777 [196]

Answer:

Step-by-step explanation:

Kindly check explanation

Step-by-step explanation:

The population of that country in 2006 was 500 million. What was the average number of

gallons of fruit juice consumed per person in the country in 2006? Use pencil and paper. Using the per

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Population of country in 2006 = 500,000,000

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Total consumption / total population

2,110,000,000 / 500,000,000

= 4.22 gallons per person

Number of gallons class will consume :

Assume number of students in class = 15

Hence, class consumption equals:

Average consumption per person × number of students in class :

4.22 × 15 = 63.3 gallons

3 0
3 years ago
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