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topjm [15]
3 years ago
10

A small fair charges an admission fee for children and adults. The cost for admission is $3 per adult and $2 per child. On a cer

tain day, total admission fees were $900, and 350 people attended the fair. How many children attended the fair that day?
Mathematics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

150 children attended the fair that day

Step-by-step explanation:

Let n represents the number of children attended.

Since there were 350 people attended, the number of adults is 350-n

Since the cost of admission is $3 per adult, the admission fee gained by adults is:

→ 3(350-n)  (1)

Since the cost of admission is $2 per child, the admission fee gained by children is:

→ 2n  (2)

Since the total admission fees were $900, the total of 1 and 2 must be equal to 900

→ 3(350-n) + 2n = 900

→ 1050 - 3n + 2n = 900

→ n = 150

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Answer:

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Step-by-step explanation:

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Since the current height is 12, the current length is 6, and the width is 3, you need to plug them into the equation.

<em>SA=2(6)(3)+2(6)(12)+2(12)(3)</em>

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Answer:

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Solving

x2 + -4y2 = 25

Solving for variable 'x'.

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Add '4y2' to each side of the equation.

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Reorder the terms:

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