The length and width of the rectangle are 7.90 inches and 31.6 inches respectively
It is given that,
Let the length of the rectangle = l
Let the width of the rectangle = w
The perimeter of the rectangle = 250 inches
l x w = 250 ....eq 1
Then,
Length is 4 times as big as width
4l = w
We need to find, the length and width of the rectangle
Putting the value of w in eqn 1
We get,




Similarly, we can get,
w = 4l
w = 4 x 7.90
w = 31.6
Hence, the length and width of the rectangle are 7.90 inches and 31.6 inches respectively
To learn more about, perimeter, here
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4. 8+12=20
4 (2+3)
First you add 2+3 and get 5
Next, since the 5 is now in the parentheses, it indicates that you have to multiply
Finally, 5 times 4=20
The correct answer is the graph in the top right corner because it is a constant function. The bottom left graph is also considered a function but is an absolute function. So both are technically correct.
2^2a^2+b^2
4a^2+b^2
not sure if this is correct but here ya go
Answer:
Step-by-step explanation:
1.95 g