1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Answer: 15°.
Step-by-step explanation:
a a a a a a a abedRounding of a number means replacing it with another number that is nearly equal to it but easy to represent or write. For example 754 rounded to nearest thousand is 1000. If the rounding number is 4 or less it is round down. If the rounding number is 5 or more it is rounded up
Answer:
110 1/4 lb
Step-by-step explanation:
To answer this, multiply 112 1/2 pounds by 49/50:
225 lb 49 11025 lb
---------- * ----- = -------------- = 110 25/100 lb = 110 1/4 lb
2 50 100
Answer:
The equations 3·x - 6·y = 9 and x - 2·y = 3 are the same
The possible solution are the points (infinite) on the line of the graph representing the equation 3·x - 6·y = 9 or x - 2·y = 3 which is the same line
Step-by-step explanation:
The given linear equations are;
3·x - 6·y = 9...(1)
x - 2·y = 3...(2)
The solution of a system of two linear equations with two unknowns can be found graphically by plotting the two equations and finding the coordinates of the point of intersection of the line graphs
Making 'y' the subject of both equations gives;
For equation (1);
3·x - 6·y = 9
3·x - 9 = 6·y
y = x/2 - 3/2
For equation (2);
x - 2·y = 3
x - 3 = 2·y
y = x/2 - 3/2
We observe that the two equations are the same and will have an infinite number of solutions
