The domain of a function contains the x-values of the function while the range of the function contains the y-values of the function. In this case, we substitute 25 and 64 to y. Then,
25 = k2 + 2 k + 1 (k-4) * (k+6) = 0
64 = k2 + 2 k + 1 (k-7) * (k+9) = 0
hence the domain is {-9,-6, 4,7}
Answer:
-7
Step-by-step explanation:
since it is the 10th term, i think you need to plug in 10 as n
which is,
3 - (10) = -7
hope it's correct and hope it helps!!
Answer:
x = (h-12y-2)/4
Step-by-step explanation:
Here, we want to make x the subject of the formula
We have this as:
h = 4x + 12y + 2
4x = h-12y-2
x = (h-12y-2)/4
So the problem has no symbols, but we're going to multiply because the fraction on the left is right next to the parentheses.
-5/2 * 1/10x = -5x/20
I put "x" next to the 5 because the "x" counts as part of the numerator. Now that it's 5x over 20 that equals one, I'd first reduce -5x/20 into -x/4, then do
-x/4 * -4 = 1 * -4
To make the "x" side equal one, we have to multiply both sides by -4, to make both sides equal.
x = -4.
