Answer:
% Free space in water = ×100 = 99.45%
% Free space in ice = ×100 = 99.8%
Explanation:
As given ,
Density for ice at 0⁰C = 0.917 g/ml
Density for water at 0⁰C = 0.999 g/ml
Radii of H atoms = 37 pm
Radii of O atoms = 66 pm
Now,
Consider 1 ml of water = 1 cm²
As , we know that mass of water in 1 cm² = 0.999 g
Moles of water =
Volume of H₂O = 1.624× m²
Now,
Volume occupied by water = 0.056×6.022×× 1.624× m²
= 5.48× m²
⇒Volume occupied by water = 5.48× m²
Now,
Free space = 1× - 5.48× = 9.95× m²
% Free space = ×100 = 99.45%
Now,
Consider 1 ml of ice = 1 cm²
S.I unit of ice = 1× m²
As , we know that mass of water in 1× m² = 0.917 g
Moles of ice =
Volume of H₂O = 6.022× ×0.012
Volume of ice unit =
Now,
Volume occupied by water = 0.012×6.022×× 1.624× m²
= 1.17× m²
⇒Volume occupied by water = 1.17× m²
Now,
Free space = 1× - 1.17× = 9.98× m²
% Free space = ×100 = 99.8%