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Vikki [24]
3 years ago
7

3 pts

Chemistry
1 answer:
elena55 [62]3 years ago
4 0

Answer:

23.56

Explanation:

We know that BaCl₂ is the limiting reactant. We can write the following:

Grams BaCl₂ * Molar Mass of BaCl₂ * Mole ratio * Molar Mass of NaCl

41.97g BaCl₂ * (1 mol BaCl₂ / 208.23g BaCl₂) * (2 mol NaCl / 1 mol BaCl₂) * (58.44g NaCl / 1 mol NaCl) = 23.56g NaCl

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