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LiRa [457]
4 years ago
6

Lithium (Li) atoms have ______ orbitals.

Chemistry
1 answer:
Hoochie [10]4 years ago
5 0

Answer:

there are 3 electrons in a lithium atom. Looking at the picture, you can see there are two electrons in shell one and only one in shell two.

Explanation:

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A student used standard solutions of aspirin in a FeCl3-KCl-HCl mixture to plot a graph of molarity versus absorbance for dilute
kvasek [131]

Answer:

is any thing which has mass volume and empty space

8 0
3 years ago
The stars are H and the circles are O by the way
shepuryov [24]

Answer:2 is correct

Explanation:

6 0
3 years ago
If our eyes could see a slightly wider region of the electromagnetic spectrum, we would see a fifth line in the Balmer series em
erica [24]

Answer: Wavelength  associated with the fifth line is 397 nm

Explanation:

E=\frac{hc}{\lambda}

\lambda = Wavelength of radiation

E= energy

For fifth line in the H atom spectrum in the balmer series will be from n= 2 to n=7.

Using Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant =10973731.6m^{-1}

n_f = Higher energy level = 7

n_i= Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

\frac{1}{\lambda}=10973731.6\times \left(\frac{1}{2^2}-\frac{1}{7^2} \right )\times 1^2

\frac{1}{\lambda}=2.52\times 10^{6}m

\lambda}=3.97\times 10^{-7}m=397 nm      1nm=10^{-9}m

Thus wavelength λ associated with the fifth line is 397 nm

7 0
4 years ago
50 POINTS!
Varvara68 [4.7K]
5.5/-38 / 5.5 = 1/-6.9 x 1.3 = 1.3/-8.98
unit volume/temperature x searching amount

i’d say the temperature would be -8.98 C simply - I don’t know what formula youd use for this

6 0
4 years ago
How do you convert 42.7L to mL
zimovet [89]
1L=1000 mL,L GOES BOTTOM AND mL GOES TOP,ANSWER SHOULD BE 42700.
4 0
4 years ago
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