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Elenna [48]
3 years ago
5

GIVING 20 POINTS!! Apply Concepts Two chemists each plan an investigation in which they will combine hydrogen gas with chlorine

gas to observe the chemical reactivity. The plans differ in that one will use 25 milligrams each of hydrogen and chlorine, and the other will use 1000 times this amount, i.e., 25 grams each of hydrogen and chlorine. Can the investigations reach similar conclusions about the reactivity of hydrogen with chlorine? Explain.
Chemistry
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

Yes, the investigations will reach similar conclusions about the reactivity of H2 and Cl2

Explanation:

1. The law of multiple proportions says that when elements form compounds, the proportions of the elements in those chemical compounds can be expressed in small whole number ratios.  This means that regardless of whether 1000 times more of the products are used, the reactivity of the products is established by the chemical reaction

2. The law of multiple proportions is an extension of the law of definite composition, which states that compounds will consist of defined ratios of elements.

3. A reaction with more reactants will need more care because more products are produced, which can be toxic

4. H2 and Cl2 reactivity does not depend on the quantities but the chemical properties of each compound

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3 years ago
<img src="https://tex.z-dn.net/?f=I_%7B2%7D" id="TexFormula1" title="I_{2}" alt="I_{2}" align="absmiddle" class="latex-formula">
gogolik [260]

Answer: I2 is the Oxidant; while the 2S2O3(-2) is the reductant.

Explanation:

An Oxidant is any substance that oxidizes, or receives electrons from, another; in so doing, it becomes reduced in oxidation number.

A Reductant thus exactly the opposite.

Note that the equation provided shows that Iodine (I2) received an electron to become NEGATIVELY CHARGED:

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The oxidation number reduced from 0 to -1.

In contrast, the oxidation number of 2S2O3(-2) increases from -4 to -2.

Thus, I2 is the Oxidant; while the 2S2O3(-2) is the reductant.

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Answer:

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