Answer:
The answer would be A to this question.
Answer:
The answer to your question is 41.6 g of AgCl
Explanation:
Data
mass of NH₄Cl = 15.5 g
mass of AgNO₃ = excess
mass of AgCl = 35.5 g
theoretical yield = ?
Process
1.- Write the balanced chemical reaction.
NH₄Cl + AgNO₃ ⇒ AgCl + NH₄NO₃
2.- Calculate the molar mass of NH₄Cl and AgCl
NH₄Cl = 14 + 4 + 35.5 = 53.5 g
AgCl = 108 + 35.5 = 143.5 g
3.- Calculate the theoretical yield
53.5 g of NH₄Cl -------------------- 143.5 g of AgCl
15.5 g of NH₄Cl ------------------- x
x = (15.5 x 143.5) / 53.5
x = 2224.25 / 53.5
x = 41.6 g of AgCl
Some physical properties would be:
appearance, odor, density, and magnetism.
Some chemical properties would be:
flammability, reaction to water oxygen or acid, decomposition caused by light or heat, and tendency to corrode.
Hope this helps. (;
Answer:
The theoretical yield of Cu(s) in moles is 60.15 moles
Explanation:
Step 1: Data given
Number of moles CuO = 70.8 moles
Number of moles NH3 = 40.1 moles
Molar mass CuO = 79.545 g/mol
Molar mass NH3 = 17.03 g/mol
Step 2: The balanced equation
3CuO(s) + 2NH3(g) → 3H2O(l) + 3Cu(s) + N2(g)
For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2
NH3 is the limiting reactant. It will completely be consumed (40.1 moles). CuO is in excess. There will react 3/2 * 40.1 = 60.15 moles
There will remain 70.8 - 60.15 = 10.65 moles CuO
Step 3: Calculate moles Cu
For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2
For 40.1 moles NH3 we'll have 60.15 moles Cu
The theoretical yield of Cu(s) in moles is 60.15 moles
Answer:
its A
Explanation:
The only one that makes sense
