Remark
<u>Two facts.</u>
1) Tan(x) = Sin(x) / Cos(x)
2) Csc(x) and Sin(x) are reciprocal relationships. When multiplied together, they equal 1.
Solution
So Csc(x) * tan(x) = csc(x) * sin(x) / cos(x) = 1/cos(x) = sec(x)
So far what we have is tan^2(x) + sec(x). We have to get rid of tan^2(x)
Use the identity of 1 + tan^2(x) = sec^2(x)
tan^2(x) = sec^2(x) - 1
sec^2(x) - 1 + sec(x)
a^2 + a - 1 <<<<<< Answer
B is the answer.
Answer:
24 minutes, 2:36 pm
Step-by-step explanation:
As working with hours is difficult because it does not use decimal system, lets work with minutes, not hours.
So, the clock is set to work normal at 3:00 pm and we need to get the minutes lost three days after. We know that, as 1 day has 24 hs, 3 days have 72 hours. Then, as our clock loses 2m after every 6 hs, we need to see how many 6hs are there in 72 hs. We do this bt dividing 72 by 6:
72/6 = 12
So, in 72 hours we will have 12 periods of 6hs. As our clock loses 2m after every 6 hs, in 3 days we will lose 2m 12 times. This is:
12 * 2 = 24
The clock loses 24 minutes.
Now we need to see the time it will read.
If there were no problems, the clock should read 3:00 pm after 3 days (72hs). But, as it lost 24 minutes, it will read 2:36 pm, it is, 24 minutes before 3:00 pm.
It’s jimins birthday today
Answer:
D
Step-by-step explanation:
given
V = 
bh
multiply both sides by 3 to eliminate the fraction
3V = bh ( divide both sides by h )
b = 
→ D
