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Makovka662 [10]
3 years ago
15

Can someone pls help ​

Mathematics
2 answers:
algol133 years ago
6 0

Answer:

square so all sides are equal

bc^2+mc^2=bm^2

16x^2+4x^2=20x^2=2root5x

nd^2+dm^2=nm^2

x^2+4x^2=5x2=root5x

then:-

1/2*b*h=1/2*2root5x*root5x

=1/2*10x^2=5x^2

harina [27]3 years ago
4 0
<h3>Answer:  5x^2</h3>

==================================

Work Shown:

ND = x

AN = 3x

MD = 2x

MC = 2x

BC = 4x

AB = 4x

-------

P = Area of square ABCD

P = (AB)^2

P = (4x)^2

P = 16x^2

-------

Q = Area of triangle ABN

Q = (1/2)*base*height

Q = (1/2)*AN*AB

Q = (1/2)*3x*4x

Q = 6x^2

-------

R = Area of triangle MBC

R = (1/2)*base*height

R = (1/2)*BC*MC

R = (1/2)*4x*2x

R = 4x^2

-------

S = Area of triangle MND

S = (1/2)*base*height

S = (1/2)*ND*MD

S = (1/2)*x*2x

S = x^2

-------

T = Area of triangle BMN

T = P - Q - R - S

T = 16x^2 - 6x^2 - 4x^2 - x^2

T = 5x^2

-------

An alternative method is to use the pythagorean theorem to find the lengths of BM and MN. Then you can directly compute the area of triangle BMN. You should find that BM = sqrt(20)*x and MN = sqrt(5)*x.

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The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

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So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

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5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Read more about polynomial at

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1 year ago
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Answer:

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