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Luda [366]
3 years ago
13

Let A and B be square matrices. Show that if ABequals=I then A and B are both​ invertible, with Bequals=Upper A Superscript nega

tive 1A−1 and Aequals=Upper B Superscript negative 1B−1.
Mathematics
1 answer:
stich3 [128]3 years ago
5 0

Step-by-step explanation:

Since AB=I, we have

det(A)det(B)=det(AB)=det(I)=1.

This implies that the determinants det(A) and det(B) are not zero.

Hence A,B are invertible matrices: A−1,B−1 exist.

Now we compute

I=BB−1=BIB−1=B(AB)B−1=BAI=BA.since AB=I

Hence we obtain BA=I.

Since AB=I and BA=I, we conclude that B=A−1.

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3 years ago
Math help please FAST
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Answer:

180

60

40

Step-by-step explanation:

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3 years ago
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Monica [59]
The value of X in the equation is -3
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The length of a side of a triangle is 26 in. A line, parallel to the given side ,divides the triangle into 2 parts of equal area
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Point B is a point of tangency. Find the radius r of OC.<br> А 9<br> B<br> r<br> n
insens350 [35]

Answer:

Radius, r, is 3.75

Step-by-step explanation:

From the given diagram,

AB = 9

AC = 6 + r

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Thus applying the Pythagoras theorem, we have;

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r = 3.75

The radius is 3.75.

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2 years ago
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