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3 years ago

The diameter of a circle that has an area of 452.16 mm

1 answer:

3 0

The diameter is 24 since if you ÷ it by 2 you get 12 to get area it is radius squared so 12 × 12= 144×pi which is 3.14= 452.16 mm you can even check in a calculator

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A square and an equilateral triangle have equal perimeters. the area of the triangle is

Ivenika [448]

a - length of side of a square

t - length of side of a triangle

The perimeter of a square: $P_S=4a$

The perimeter of a triangle: $P_T=3t$

We have the area of a triangle: $A_T=16\sqrt3\ cm^2$

The formula of an area of an equilateral trinagle: $A_T=\dfrac{t^2\sqrt3}{4}$

Substitute:

$\dfrac{t^2\sqrt3}{4}=16\sqrt3$ multiply both sides by 4

$t^2\sqrt3=64\sqrt3$ divide both sides by $\sqrt3$

$t^2=64\to t=\sqrt{64}\to t=8\ cm$

The perimeter of a triangle: $P_T=3(8)=24\ cm$

Substitute to the formula of a perimeter of a square:

$4a=24$ divide both sides by 4

$a=6\ cm$

The formula of a diagonal of a square: $d=a\sqrt2$

Substitute:

$d=6\sqrt2\ cm$

3 0

2 years ago

Henry rolls a standard six-sided die, numbered from 1 to 6. Which word or phrase describes the probability that he will roll a m

DanielleElmas [232]

The answer I would assume is C

7 0

2 years ago

A plastic box has a length 4 cm longer than its width. The area of the rectangular top of the box is 77 square cm. Find the leng

finlep [7]

Answer: the length is 11 cm.

The width is 7 cm.

Step-by-step explanation:

Let L represent the length of the rectangular plastic box.

Let W represent the width of the rectangular plastic box.

The area of the rectangular top of the box is 77 square cm. This means that

LW = 77- - - - - - - ;- - - -1

The plastic box has a length 4 cm longer than its width. This means that

L = W + 4

Substituting L = W + 4 into equation 1, it becomes

(W + 4)W = 77

W² + 4W = 77

W² + 4W - 77 = 0

W² + 11W - 7W - 77 = 0

W(W + 11) - 7(W + 11) = 0

W - 7 = 0 or W + 11 = 0

W = 7 or W = - 11

Since the width cannot be negative, then W = 7cm

L = 77/7 = 11 cm

4 0

3 years ago

(g(1) = 50 (g(n) = 8 - g(n-1) g(2) =

Finger [1]

G is the same function

Using the 2nd function

g(2) = 8 - g(2-1)
g(2) = 8 - g(1) (g(1)=50 )
So, g(2)= 8-50
g(2) = -42

5 0

3 years ago

Read 2 more answers

• a helicopter hovering at 10 m above the ground is shining a spotlight at a person 30 m away1 . if the person is 2 m tall how l

pshichka [43]

As shown in the figure

Height of helicopter above the ground=30 m

Distance from the base to the point where the person is standing=30 m

height of the person=2 m

Now the person cast the shadow of length x m.

Triangle ABC and triangle EDC are similar.

∵ ∠B= ∠D=90°

∠C is common.

So by AA similarity ΔABC and ΔEDC are similar.

As we know when triangles are similar their sides are proportional.

AB/AD =BC/DC

Let DC=x meter

⇒ $\frac{10}{x}=\frac{30+x}{x}$

⇒5=\frac{30+x}{x}[/tex]

⇒5x=30+x

⇒4x = 30

⇒ x=30/4

⇒ x=7.5 meter

So length of shadow=7.5 meter

2. volume of a sphere of radius r is v (r) = $\frac{4}{3}π r^{3}$

$\frac{\mathrm{d} }{\mathrm{d} r}V$ =4/3π×3 $r^2$

=4π $r^2$

surface area of a sphere of radius r is 4π $r^2$

b) Ratio of derivative of volume of sphere to surface area of sphere= $\frac{4\pi r^2}{4\pi r^2}$

=1 [ incomplete question but you have written few words ]

4 0

2 years ago