Answer:
1. The car is slowing down at a rate of 2.5mph/s
2. The greatest acceleration is 10 mph/s.
3. In the interval 4s to 16s the speed remains constant and has magnitude 25 mph.
Step-by-step explanation:
1. The deceleration of the car is from 16 seconds to 24 seconds is the slope
of the graph from 16 to 24:

the negative sign indicates that it is deceleration.
2. The automobile experiences the greatest change in speed when the slope is greatest because that is when acceleration/deceleration is greatest.
From the graph we see that the greatest slope of the graph is between 28 and 24 seconds. The acceleration the interval is the slope
:

3. The automobile experiences no acceleration in the interval 4 s to 16 s—that's the graph is flat.
The speed of the automobile in that interval, as we see from the graph, is 25 mph.
Answer:
wheres the problem
Step-by-step explanation:
Answer:
Step-by-step explanation:
The easier way to figure this is by using the concept of torque in physics. If the torque of the man is greater than that experienced by the box, the lever will tilt in the man's favor (in other words, he will move down and the box will be lifted). Torque is found by multiplying the perpendicular force by the length of the lever arm. Because we want the man's torque to be greater than the box's torque, the inequality is:
and
That decimal is 6 inches in terms of meters.
180r > 76.2 so
r > .42 meters or `16.67 inches. The man has to sit at a distance greater than 16.67 inches in order for the box to be lifted by the lever.
In every case, you're finding the surface area of a rectangular prism. That area is the sum of the areas of the 6 rectangular faces. Since opposite faces have the same area, the formula can be written
... S = 2(LW +WH +HL)
The number of multiplications can be reduced if you rearrange the formula to
... S = 2(LW +H(L +W))
where L, W, and H are the length, width, and height of the prism. (It does not matter which dimension gets what name, as long as you use the same number for the same variable in the formula.)
When you're evaluating this formula over and over for diffferent sets of numbers, it is convenient to let a calculator or spreadsheet program do it for you.
1. S = 2((5 cm)(5 cm) +(5 cm)(5 cm +5 cm)) = 2(25 cm² +(5 cm)(10 cm))
... = 2(25 cm² + 50 cm²) = 150 cm²
2. S = 2(12·6 + 2(12+6)) mm² = 2(72 +36) mm² = 216 mm²
3. S = 2(11·6 + 4(11 +6)) ft² = 2·134 ft² = 264 ft²
4. S = 2(10·4 +3(10 +4)) in² = 164 in²