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Phantasy [73]
4 years ago
5

Consider the car driving around a circular track. Once started, the driver maintains a speed of 45 m/h. Compare the driver's vel

ocity with his acceleration in this case.
A) The car is accelerating because it is changing direction but the velocity is constant.
B) The car is traveling at a constant rate of speed so it is not accelerating and the velocity does not change.
C) Acceleration is the change in velocity so the car is experiencing a change in velocity and it is accelerating.
D) The car is traveling at a constant rate of speed so it is not accelerating but the velocity changes because the direction the car travels is constantly changing.

Physics
1 answer:
vlada-n [284]4 years ago
6 0

it is actually c because the acceleration is the change in velocity so the car is experiencing a change in velocity and it is accelerating.

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You are to drive to an interview in another town, at a distance of 300 km on an expressway. The interview is at 11:15 a.m. You p
gladu [14]

Answer:

v = 133.5 km/h

Explanation:

As we know that the distance moved by the car is given 300 km

first it move for 120 km with speed

v = 100 km/h

so the time taken by car to move this distance is

t = \frac{d}{v}

t = \frac{120}{100}

t = 1.2 h

Now it moves next 43.0 km with speed 42 km/h

so the time taken by it is given as

t = \frac{43}{42}

t = 1.02 h

now total time of journey is

t = 11:15 AM - 8 AM = 3.25 h

time remaining to cover the last part of journey is

\Delta t = 3.25 - (1.02 + 1.2) = 1.026 h

now the remaining distance is

d = 300 - 120 - 43 = 137 km

so the speed of the car is given as

v = \frac{137}{1.026}

v = 133.5 km/h

8 0
3 years ago
Two golf balls are hit from a flat field, each at an angle 30o above the horizontal. Initial speed of ball 2 is twice the initia
Lapatulllka [165]
The range, R, of a projectile based on its angle of projection ∅ and velocity v can be directly calculated by:
R = (v²sin2∅)/g
Let the v of ball 1 be v₁
R₁ = (v₁²sin(2*30))/g
v₂ = 2v₁
R₂ = ((2v₁)²sin(2*30))/g
R₂ = 4[(v₁²sin(2*30))/g]
R₂ = 4R₁
So ratio of d2/d1 = 4
4 0
3 years ago
A cricket ball has mass 0.155 kg. If the velocity of a bowled ball has a magnitude of 35.0 m/s and the batted ball's velocity is
FinnZ [79.3K]

Answer:

Magnitude of change in momentum = 4.65 kg.m/s

Magnitude of impulse = 4.65 kg.m/s

Magnitude of the average force applied by the bat = 1550 N

Explanation:

Mass of the cricket ball, m = 0.155 kg

Initial velocity of the ball, u = 35.0 m/s

final velocity of the ball after hitting the bat, v = 65.0 m/s

Time of contact, t = 2.00 ms = 2.00 × 10⁻³ s

Now,

Magnitude of change in momentum = Final momentum - Initial momentum

or

Magnitude of change in momentum = ( m × v ) - ( m × u )

or

Magnitude of change in momentum = ( 0.155 × 65 ) - ( 0.155 × 35 )

or

Magnitude of change in momentum = 10.075 - 5.425 = 4.65 kg.m/s

Now, Magnitude of impulse = change in momentum

thus,

Magnitude of impulse = 4.65 kg.m/s

Now,

magnitude of the average force applied by the bat = \frac{\textup{Impulse}}{\textup{Time}}

or

magnitude of the average force applied by the bat = \frac{\textup{4.65}}{\textup{3}\times\textup{10}^{-3}}

or

Magnitude of the average force applied by the bat = 1550 N

6 0
4 years ago
Ingrid is jogging at 9 km/h, she tosses a relay stick at 16 km/h to her teammate. How fast is the relay stick moving relative to
sesenic [268]

Answer:

27km/h

Explanation:

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3 years ago
Name and explain two sleeping disorders
vfiekz [6]
Insomnia and night terrors
4 0
3 years ago
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