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Makovka662 [10]
3 years ago
9

Name and explain two sleeping disorders

Physics
1 answer:
vfiekz [6]3 years ago
4 0
Insomnia and night terrors
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Which of the following is an incorrect statement of one of newtons laws of motion?
weqwewe [10]

Explanation:

The newton's laws of motion are:

First law:

  "A body will remain in its state of rest or of uniform motion along a path unless it is acted upon by an external force. ".

This is popularly called the law of inertia.

Second law:

 "the acceleration of a body is produced by a net force that is inversely proportional to the mass of the body".

Third law:

  "action and reaction forces are equal and opposite in direction".

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

5 0
3 years ago
Ed rolls a ball forward across the floor. It hits a wall 12 meters away and rolls back along the same path. It stops 5 meters fr
slamgirl [31]
I believe it's 7 meters positive (foward)
8 0
3 years ago
Read 2 more answers
Based on what you know, please list at least 4 characteristics of weather. IDK IF RIGHT SUBJECT
Bas_tet [7]
Rain sleet hail and snow
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3 years ago
William Tell shoots an apple from his son's head. The speed of the 102-g arrow just before it strikes the apple is 26.7 m/s, and
xxMikexx [17]

To develop the problem, we require the values concerning the conservation of momentum, specifically as given for collisions.

By definition the conservation of momentum tells us that,m_1V_1+m_2V_2 = (m1+m2)V_f

To find the speed at which the arrow impacts the apple we turn to the equation of time, in which,

t= \sqrt{\frac{2h}{g}}

The linear velocity of an object is given by

V=\frac{X}{t}

Replacing the equation of time we have to,

V_f = \frac{X}{t}\\V_f =\frac{X}{\sqrt{\frac{2h}{g}}}\\V_f = \frac{6.9}{\sqrt{\frac{2(1.85)}{9.8}}}\\V_f = 11.23m/s

Velocity two is neglected since there is no velocity of said target before the collision, thus,

m_1V_1 = (m1+m2)V_f

Clearing for m_2

m_2 = \frac{m_1V_1}{V_f}-m_1\\m_2 = \frac{(0.102)(26.7)}{11.23}-0.102\\m_2 = 0.1405KG= 140.5g

8 0
3 years ago
In deep space, sphere A of mass MA is located at the origin of an x axis and sphere B of mass MB is located on the axis at a poi
Nookie1986 [14]

Answer:

The gravitational potential energy of the two-sphere system just as B is released is

U = -[(G)(MA)(MB)/x₁]

where G = Gravitational constant

G = (6.7 × 10⁻¹¹) Nm²/kg²

Explanation:

The gravitational potential energy of two masses (m and M), separated by a distance, d, is given as

U = -(GMm/d)

For our question,

Mass of object 1 = MA

Mass of object 2 = MB

Distance between them = x₁

U = -[(G)(MA)(MB)/x₁]

where G = Gravitational constant

G = (6.7 × 10⁻¹¹) Nm²/kg²

Hope this Helps!!!

6 0
3 years ago
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