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Gnom [1K]
3 years ago
5

I need help with 5 please and thank you

Physics
1 answer:
Likurg_2 [28]3 years ago
7 0

Answer: A

Explanation:

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The frequency of the applied RF signal used to excite spins is directly proportional to the magnitude of the static magnetic fie
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Complete Question

The complete question is shown on the first uploaded image  

Answer:

The uncertainty in inverse frequency is  \Delta  [\frac{1}{w} ]=  \frac{3}{2000} \ s

Explanation:

From the question we are told that

   The value of the proportionality constant is  k  = 5  \frac{Hz }{T}

   The strength of the magnetic field is  B = 20 \ T

   The change in this strength of magnetic field is  \Delta B = 3  \ T

The magnetic field is given as

           B  =  \frac{k}{\frac{1}{w} }

Where w is frequency

The uncertainty or error of the field is given as

         \Delta  B  =  \frac{k }{[\frac{1}{w}^]^2 }  \Delta [\frac{1}{w} ]

The uncertainty in inverse frequency is given  as

           \Delta  [\frac{1}{w} ]  = \frac{\Delta B}{k [\frac{1}{w^2} ]}

                    \Delta  [\frac{1}{w} ]=  \frac{\Delta B}{k (B)^2 }

substituting values

                  \Delta  [\frac{1}{w} ]=  \frac{3}{5 (20)^2 }

               \Delta  [\frac{1}{w} ]=  \frac{3}{2000} \ s

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HURRYYYWhich tools do meteorologists use to collect data about the weather?
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A hockey puck with a mass of 0.18 kg is at rest on the horizontal frictionless surface of the rink. A player applies a horizonta
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Hello!

\large\boxed{0.018 N}

Begin by finding the acceleration of the puck. Use the kinematic equation:

d = v_{i} + \frac{1}{2}at^{2}

The initial velocity is 0 m/s since the object was at rest, so we can rewrite the equation as:

d =  \frac{1}{2}at^{2}

Plug in the given distance and time:

1.25 = \frac{1}{2}a(5^{2})\\\\2.50 = 25a\\\\a = 0.1 m/s^{2}

Find the net force using the formula F = m · a (Newton's Second Law)

F = 0.18 · 0.1

F = 0.018 N

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