Answer:
(2×2×2)×(2×2×2)×(2×2×2)×(2×2×2)×-(2×2×2)×(2×2×2)

<em><u>Solution:</u></em>
From given question,
Number of pounds Jake carry = 
Number of pounds his father carry is
times as much as jake
To find: Number of pounds Jake father can carry
<em><u>Convert the mixed fractions to improper fractions</u></em>
Multiply the whole number part by the fraction's denominator.
Add that to the numerator.
Then write the result on top of the denominator

<em><u>Then according to question,</u></em>


Answer:
Step-by-step explanation:
<u>Use properties of exponents:</u>
<u>Simplify the given expression:</u>
- 3⁴⋅x⋅(3/x²)⁻² =
- 3⁴·x·(3x⁻²)⁻² =
- 3⁴·x·(3⁻²)(x⁻²ˣ⁻²) =
- 3⁴⁻²·x¹⁺4 =
- 3²·x⁵ =
- 9x⁵
Same . It’s not giving me a lot of information!!
Answer:
$1
Step-by-step explanation: