Answer:
4c^2+7c-5=0
4c^2+7c=5
4c^2+7c=5
4c^2+7c-5=0\quad :\quad c=\frac{-7+\sqrt{129}}{8},\:c=\frac{-7-\sqrt{129}}{8}\quad \left(\mathrm{Decimal}:\quad c=0.54472\dots ,\:c=-2.29472\dots \right)
Hope This Helps!!!
You would add like terms so it would be 1x then you add 1 to 7 so you would get 8.. the you divide both sides by 1x and you'd get 8=x
Answer:
give me brainliest
Given a line AB with Point C outside it.
Mark point D on the line AB. Join CD
With D as center, and any radius, draw an arc intersecting AB at E, and CD at F.
With C as center, and same radius as before, draw an arc intersecting CD at G.
Open a compass to length EF
Now,with G as center, and compass opened the same radius as before, draw an arc intersecting the previous arc at H.
Draw a line m passing through C and H.
Thus m is the line parallel to AB, and passing through point C
∴m∣∣AB
Step-by-step explanation:
You could say that, "Mr.Fuller has 2 2/3 pies left over from his party.