Answer:
so basically anyhting over 295 :)
Explanation:
331.35 = 175 + (0.53m)
156.35 = 0.53m
295 = m
Answer:
Joint costs allocated to Product Y = $60,000
Explanation:
Given:
Particular Product Units Produced Sales
X 5,000 $70,000
Y 3,000 $30,000
<u>Z 2,000 $100,000</u>
<u>Total 10,000 </u>
Joint costs allocated to Product Y = (Total Joint costs × Y's total unit) / Total units produced
Joint costs allocated to Product Y = ($300,000 × 3,000) / 10,000
Joint costs allocated to Product Y = $90,000
Answer:
Profit Maximising Quantity = 775
Explanation:
Price P = 35 - 0.02Q
Total Revenue TR = Price x Quantity = P X Q
= (35 - 0.02Q)(Q) = 35Q - 0.02Q^2
Total Cost TC = 8000 + 4Q
Profit = TR - TC
[35Q - 0.02Q^2] - [8000+4Q] = 35Q - 0.02Q^2 - 8000 - 4Q
Profit Function = - 0.02Q^2 + 31Q - 8000
To find out profit maximising Quantity , we will differentiate Profit Function with respect to Q & equate it to 0.
dTR/ dQ = -0.04Q + 31 = 0
Q = 31/0.04 = 775
To verify whether 775 is profit maximising Q, we will do second derivative & check that it is negative.
d^2TR/ dQ^2 = -0.04 i.e < 0 (negative)
So 775 is profit maximising quantity
Answer:
c. $480,930
Explanation:
In this method we applied the unitary method
Given that
Sales volume = 40,000 units
Sales = $492,000
Sales volume = 39,100 units
Sales = ?
So, by considering the given information, the sales for 39,100 units would be
= Sales × updated sales units ÷ last sales units
= $492,000 × 39,100 units ÷ 40,000 units
= $480,930