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3 years ago

10

Help with some homework please

1 answer:

LUCKY_DIMON [66]3 years ago

8 0

Sorry I don’t get this one anymore ???

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Solve 3 over x minus 3 equals the quantity of x over x minus 3, minus three-halves. for x and determine if the solution is extra

astraxan [27]

$\frac{3}{x} -3 = \frac{x}{x} - \frac{3}{2}$
$3 -3x = x - \frac{3x}{2}$
$-6x -2x -x = 6$
$-9x=6$
$9x=6$
$x= \frac{6}{9}= \frac{2}{3}$

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3 years ago

Divide 3x ^ 3 + 7x ^ 2 - 8x + 48 by x + 4

Akimi4 [234]

Answer: 3x 3 +7x 2 +40x+4

Step-by-step explanation: Hope that helps

8 0

3 years ago

Can anyone help me out with these two problems please? Thanks!

V125BC [204]

1) x = 60/31 = 1.935
2.) m = 8/3 = 2.667
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3 years ago

What is 4*54<br> brainiest

nirvana33 [79]

Answer:

2 x54 + 2 x 54

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216

Step-by-step explanation:

8 0

3 years ago

Can someone please help me solve these two problems and explain them to me? About the one with proportions though... I've always

NeTakaya

Answers:

A) $-\frac{11}{4}$

C) $m_{1}=\frac{Fr^{2}}{G m_{2}}$

Step-by-step explanation:

<u>Part 1:</u>

We have the followig equation:

$\frac{x-1}{3}-\frac{x+4}{5}=\frac{4x-1}{8}$

Calculating the least common multiple (l.c.m) in the denominator in the left side of the equation, being l.c.m=15:

$\frac{5(x-1)-3(x+4)}{15}=\frac{4x-1}{8}$

Solving for the left part of the equation:

$\frac{2x-17}{15}=\frac{4x-1}{8}$

Operating with cross product:

$8(2x-17)=15(4x-1)$

Applying the distributive property:

$16x-136=60x-15$

Isolating $x$ :

$x=-\frac{121}{44}$

Dividing numerator and denominator by 11:

$x=-\frac{11}{4}$ Hence, the correct option is A

<u>Part 2:</u>

We have the followig equation:

$F=\frac{G m_{1} m_{2}}{r^{2}}$

Operating with cross product:

$Fr^{2}=G m_{1} m_{2}$

Isolating $m_{1}$ :

$m_{1}=\frac{Fr^{2}}{G m_{2}}$ Hence, the correct option is C

5 0

3 years ago