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Gre4nikov [31]
3 years ago
7

Solve for n. 7n − 10 = –2n − 10 n =

Mathematics
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

n=4

Step-by-step explanation:

7n-10=-2n-10

5n=20

n=4

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The answer is given above

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Consider the composite function (g (x) ) = StartRoot StartFraction 1 Over x squared minus 3 EndFraction EndRoot. If g(x) = x2 –
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The answer is C on edge

Step-by-step explanation:

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3 years ago
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Ms. Owens has 15 cars. Ms, Cook took some. Now she has 11 left. How many cars did Ms. Cook take?
nasty-shy [4]

Answer:

4

Step-by-step explanation:

The total number of cars Ms. Owens has is 15.

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3 years ago
Help me??? lol i dont get this
Anon25 [30]

Answer: 200 in squared

Step-by-step explanation:

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Take the white triangle and substitute it for one of the black ones. Now, you have this.

Now, just do 10 * 20

= 200

8 0
3 years ago
PLEASE HELPP also sorry the photo is sideways
dybincka [34]
<h2>a) Select all that apply</h2>

\overline{LL'}, \ \overline{MM'} \ and \ \overline{NN'}<em> are each perpendicular to the line of reflection</em>

<em></em>

This option is the only one that is correct. The line of reflection is  y=-1. When we talk about reflection, we are talking about reflecting across a line, or axis. Reflecting a shape means looking at the mirror image on the other side of the axis. So in this case, this mirror is the line of reflection.  As you can see, these three segments \overline{LL'}, \ \overline{MM'} \ and \ \overline{NN'}<em> </em>form a right angle at the point each segment intersects the line y=-1.

<h2>b) Find each length</h2>

Since the line y=-1 is an axis that allows to get a mirror image, therefore it is true that:

\overline{LS}=\overline{L'S} \\ \\ \overline{MT}=\overline{M'T} \\ \\ \overline{NU}=\overline{N'U}

To find those values \overline{LS}, count the number of units you get from the point S to L, which is 3 units. Do the same to find \overline{MT} but from the point T to M, which is 6 units and finally, for \overline{NU} but from the point U to N, which is 4 units. Therefore:

\overline{LS}=\overline{L'S}=3 \ units \\ \\ \overline{MT}=\overline{M'T}=6 \ units \\ \\ \overline{NU}=\overline{N'U}=4 \ units

<h2>c) Correct Statement</h2>

<em>The line of reflection is the perpendicular bisector of each segment joining a point and its image. </em>

<em />

A bisector is the line dividing something into two equal parts. In this case, the line of reflection divides each segment into two equal parts and is perpendicular because this line form a right angle with each segment. As we demonstrated in a) each segment is perpendicular to the line of reflection, so the first statement is false. On the other hand, each side of the original triangle is not perpendicular to its image and this is obvious when taking a look at the figure. Finally, as we said the line of reflection is perpendicular to each of the mentioned segments, so they can't be parallel as established in the last statement.

5 0
3 years ago
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