Given: ∠A is a straight angle. ∠B is a straight angle.
We need to Prove: ∠A≅∠B.
We know straight angles are of measure 180°.
So, ∠A and <B both would be of 180°.
It is given that ∠A and ∠B are straight angles. This means that <u>both angles are of 180°</u> because of the <u>the definition of straight angles</u>. Using <u>the definition of equality</u>, m∠A=m∠B . Finally, ∠A≅∠B by <u>definition of congruent. </u>
Answer:
Step-by-step explanation:
y = 3x + 2
6x – 2y = 10
Ryan’s answer:
I solved by adding the equations. The solution is .
y = 3x + 2 → 3x + y = 2
6x – 2y = 10 → 3x – y = 5
6x = 7
x =
6x – 2y = 10 → 6 – 2y = 10
7 – 2y = 10
–2y = –3
y = -
Jesse’s answer:
I used matrices. The solution is .
Mark’s answer:
I graphed the equations. The lines are parallel and do not intersect, so there is no solution.
1 and 2 are equations and 3 is a solution
Answer:
6x - 11y = -13 is the answer.
Step-by-step explanation:
Let's plug in the points to see what sticks.
Start with (-4, -1)
1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 
13
2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13
3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 17
4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 13
The only one that fits is #2. Let's try the other point to be sure.
2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13
Yes because they both have the same degrees, but one is slightly rotated
