The questions given in the pdf are these pictures, then we can get the solutions.
<u>1) Solution</u>
It is given that,
→ <5 = <6
Then the co interior angles,
→ <5+ <4 = 180°
Now substituting value of <5,
→ <6+ <4 = 180°
This shows property of co interior angle.
Therefore, L II m.
<u>2) Solution</u>
Take it as,
→ <1= 90°
In above eq. L is perpendicular to t.
→ <2 = 90°
In above eq. m is perpendicular to t.
Then it will be,
→ <1 = <2
It shows property of corresponding angle.
Therefore, L II m.
<u>3) Solution</u>
It is given that,
→ <1 = <2 and <1 = <3
Now substitute,
The value of <1 in second one,
→ <2 = <3
This shows property of alternate angle.
Therefore, ST II UV.
<u>4) Solution</u>
It is given that,
→ <RSP = <PQR --- (1)
→ <QRS + <PQR = 180° --- (2)
Now from the equation (1) and (2),
→ <RSP + <QRS = 180°
It shows property of co interior angle.
Therefore, PS II QR.
Answer:
488
Step-by-step explanation:
= 0 - replace x = -9 => 6 x (-9)^2 + 2 = 488
Answer:
B
Step-by-step explanation:
I got it right on the test
The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years, is 540 grams.
<h3>What is half-life?</h3>
This can be defined as the time taken for half the amount of a radioactive substance to decay.
To calculate the amount of cesium left after 120 years, we use the formua below.
Formula:
- R' = R/(
)............. Equation 1
Where:
- R = Original amount of Cesium
- R' = New amount of cesium
- T = Total time
- t = Half-life
From the question,
Given:
- R = 8640
- T = 120 years
- t = 30 years
Substitute these values into equation 1
- R' = 8640/(
) - R' = 8640/

- R' = 8640/16
- R' = 540 grams.
Hence, The mass of cesium left afer 120 years is 540 grams.
Learn more about half-life here: brainly.com/question/25750315