Yes, 104.12 is greater than 104.002
because 104.12 rounds up to 104.1
and 104.002 rounds up to 104.0
Answer:
Refer below
Step-by-step explanation:
a) a and b are the lower and higher values of the interval for which uniform distribution is defined.
Here a= 6 and b =10
b) Mean of the uniform distribution= (a+b)/2 = (6+10)/2 =8
Or int x (1/4) dx = x^2/8 = 8
c) Variance of the uniform distribution = (b^2-a^2)/12 = (100-64)/12
= 36/12 =3
Std dev = sq rt of 3 = 1.732
d) To find total area
PDF of the distribution = 1/(b-a) = 1/4, 6<x<10
Area = \int 6 to 10 of 1/4 dx
= x/4
Subtitute limits
= (10-6)/4 =1
So total area = 1
d)P(X>7) = int 7 to 10 of 1/4 dx = 3/4
e) P(7<x<9) = Int 7 to 9 of 1/4 dx = 2/4 = 1/2
Answer:
6
Step-by-step explanation:
n ! = n(n - 1)(n - 2)..... × 3 × 2 × 1
Given
(n - 1) ! with n = 4, then
(4 - 1) !
= 3 ! = 3 × 2 × 1 = 6
Answer:
5x+1
Step-by-step explanation:
