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3 years ago

the product of 7 and a number increased by 3 is equal to twice the number subtracted from 39 find the number

2 answers:

4 0

Say x is the number

7x +3 = 39 -2x
Add 2x to each side
9x +3 =39
Subtract 3 from each side
9x =36
Divide by 9 on each side
x=4

Hope this helped

Neporo4naja [7]3 years ago

4 0

Answer: The required number is 2.

Step-by-step explanation: Given that the product of 7 and a number increased by 3 is equal to twice the number subtracted from 39.

We are to find the number.

Let x represents the given number.

Then, according to the given information, we have

$7(x+3)=39-2x\\\\\Rightarrow 7x+21=39-2x\\\\\Rightarrow 7x+2x=39-21\\\\\Rightarrow 9x=18\\\\\Rightarrow x=\dfrac{18}{9}\\\\\Rightarrow x=2.$

Thus, the required number is 2.

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3 years ago

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-------------------------------------
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Parallelogram ABCD has vertex coordinates a(0,2) b (6,2) c (8,6 and d (2,6) write a rule to find the vertex coordinates of a par

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