Question

the product of 7 and a number increased by 3 is equal to twice the number subtracted from 39 find the number

Answer 1

Say x is the number

7x +3 = 39 -2x
Add 2x to each side
9x +3 =39
Subtract 3 from each side 
9x =36
Divide by 9 on each side
x=4

Hope this helped

Answer 2

Answer:  The required number is 2.

Step-by-step explanation:  Given that the product of 7 and a number increased by 3 is equal to twice the number subtracted from 39.

We are to find the number.

Let x represents the given number.

Then, according to the given information, we have

$7(x+3)=39-2x\\\\\Rightarrow 7x+21=39-2x\\\\\Rightarrow 7x+2x=39-21\\\\\Rightarrow 9x=18\\\\\Rightarrow x=\dfrac{18}{9}\\\\\Rightarrow x=2.$

Thus, the required number is 2.