Answer:
Wonka bars=3 and Everlasting Gobstoppers=24
Step-by-step explanation:
let the wonka bars be X
and everlasting gobstoppers be Y
the objective is to
maximize 1.3x+3.2y=P
subject to constraints
natural sugar
4x+2y=60------1
sucrose
x+3y=75---------2
x>0, y>0
solving 1 and 2 simultaneously we have
4x+2y=60----1
x+3y=75------2
multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have
4x+2y=60
4x+12y=300
-0-10y=-240
10y=240
y=240/10
y=24
put y=24 in equation 2 we have'
x+3y=75
x+3(24)=75
x+72=75
x=75-72
x=3
put x=3 and y=24 in the objective function we have
maximize 1.3x+3.2y=P
1.3(3)+3.2(24)=P
3.9+76.8=P
80.7=P
P=$80.9
Answer:
Step-by-step explanation:
They both (36 and 45) go into 9. Divide them both by 9.
Answer:
A=60, B=80, and C=67
Step by step explanation:
B= 2a
C= a+27
With the information, you get the equation:
A+A+27+2A=187
Then, you have to simplify.
You then get 4a+27=187.
Now, you subtract 27 from both sides to get: 4a=60.
Divide both sides by 4 to get A= 60.
If A=60, 2A=80, so B=80. A+27=67, so C=67.
You check this by adding them up to see if they equal to 187, which in fact, they do.
A=60, B=80, and C=67.
Hope this helped!
