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GuDViN [60]
4 years ago
6

NEED HELP ASAP PLEASE

Mathematics
2 answers:
ki77a [65]4 years ago
5 0
D.) is the right answer
OverLord2011 [107]4 years ago
3 0
D is right as the conditions suit to the given situation
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Let g(x)=6-2x then g(0)=<br><br> Simple functions
Aleonysh [2.5K]
<h3>Given :</h3>

\tt g(x)=6-2x

<h3>To Find :</h3>

\tt g(0)= ?

<h3>Solution :</h3>

\tt g(x)=6-2x

\tt By \: putting \: x = 0

\tt \implies g(0)=6-2(0)

\tt \implies g(0)=6 - 0

\tt \implies g(0)= 6

\pink{\tt \therefore \: value \: of \: g(0)= 6}

6 0
3 years ago
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Can someone help me with this and explain it?
Softa [21]

Answer:

4 pizzas

Step-by-step explanation:

Equation:

12x + 7 = 55

12x = 55 - 7

12x = 48

x = 4

4 0
3 years ago
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Oksanka [162]
I took the quiz the answer is A,B,D,E
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4 0
3 years ago
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Intro to ratios <br> in simplified ratio of circles to squares
svlad2 [7]

Answer:

...

Step-by-step explanation:

2:4

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3 0
3 years ago
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
natulia [17]

Answer:

g'(x)=\frac{2e^x-e^{-\frac{x}{2}}}{2(e^x+e^{-\frac{x}{2}})}

Step-by-step explanation:

We are given that a function

g(x)=ln(e^x+e^{-\frac{x}{2}})

We have to find the derivative of function

Differentiate w.r.t x

g'(x)=\frac{1}{e^x+e^{-\frac{x}{2}}}\times (e^x+e^{-\frac{x}{2}}\times (-\frac{1}{2}))

By using formula

\frac{d(lnx)}{dx}=\frac{1}{x}

\frac{d e^x}{dx}=e^x

g'(x)=\frac{e^x-\frac{e^{-\frac{x}{2}}}{2}}{e^x+e^{-\frac{x}{2}}}

Hence, the derivative function

g'(x)=\frac{2e^x-e^{-\frac{x}{2}}}{2(e^x+e^{-\frac{x}{2}})}

3 0
4 years ago
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