5n(3n+8) ..? I don't understand

It is given that the estimated employment change by sector 2004–2020 a bar graph titled estimated employment change by sector from 2004 to 2020 has the year on the x-axis and the percentage of change in employment on the y-axis.

It is required to find the correct statement.

<h3>What is a bar chart?</h3>

It is defined as the visual way to show the data a systematically with rectangle box on the x-axis and y-axis. The height and vertical lines show the proportional data.

From the given data many businesses stagnated and had to fire employees, but these were primarily people who could be quickly replaced by someone willing to work for a lower wage.

Employees in the high-tech sector are frequently too valuable to the company to be laid off, therefore their job security was strong because no one could replace them.

Thus, the high-tech sector employees were less likely to lose their jobs option fourth is correct.

Learn more about the bar chart here:

brainly.com/question/15507084

8 0

2 years ago

If Store B sells 12 bottles for $3.50... What is the price for 1 bottle at Store B?

Lena [83]

Answer:

0.29 cents a bottle at store B

Step-by-step explanation:

devide the price by the amount of products. called the unit price

4 0

3 years ago

A doctor released the results of clinical trials for a vaccine to prevent a particular disease. In these clinical trials, 200,0

CaHeK987 [17]

Answer:

1) No, there is not enough evidence to support the claim that the vaccine was effective (P-value=0.104) .

The null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

being the subindex 1 for the experimental group and subindex 2 for the control group.

2) Test statistic z=-1.26

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the vaccine was effective.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

The significance level is 0.01.

The sample 1 (experimental group), of size n1=100000 has a proportion of p1=0.0002.

$p_1=X_1/n_1=21/100000=0.0002$

The sample 2 (control group), of size n2=100000 has a proportion of p2=0.0003.

$p_2=X_2/n_2=30/100000=0.0003$

The difference between proportions is (p1-p2)=-0.0001.

$p_d=p_1-p_2=0.0002-0.0003=-0.0001$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{21+30}{100000+100000}=\dfrac{51}{200000}=0.00026$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.00026*0.99974}{100000}+\dfrac{0.00026*0.99974}{100000}}\\\\\\s_{p1-p2}=\sqrt{0+0.0000000025}=\sqrt{0.0000000051}=0.000071$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.00009-0}{0.000071}=\dfrac{-0.00009}{0.000071}=-1.26$

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=P(z$

As the P-value (0.104) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the vaccine was effective.

6 0

3 years ago