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3 years ago

What is the domain range and zeros of the graph ?

Mathematics

1 answer:

marusya05 [52]3 years ago

8 0

The domain is how far the graph stretches horizontally (on the x-axis).

Domain: ( -∞ , ∞ ) or -∞ < x < ∞

The range is how long the graph stretched vertically (on the y-axis).

Range: ( -∞ , 2 ] or -∞ < y ≤ 2

The zeros are where the graph intersects with the x-axis. In other words, the x-values when y=0.

Zeros: x = -1 and x = 3

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How many bottles of chocolate can you buy with $20 if one cost $4? One step equation

Ulleksa [173]

You can buy 5 bottles because $4 times 5 equals $20. I hope this helps :)

6 0

3 years ago

Read 2 more answers

A sphere and a cylinder have the same radius and height. The volume of the cylinder is . Amie found the volume of the sphere. He

dezoksy [38]

Amie's error while measuring the volume of a sphere is that Amie should have multiplied 54 by 2/3. Thus, the first option is the right choice.

In the question, we are given that a sphere and a cylinder have the same radius and height.

We assume the radius of the sphere to be r, and its height to be h.

Now, the height of a sphere is its diameter, which is twice the radius.

Thus, the height of the sphere, h = 2r

Given that the sphere and the cylinder have the same radius and height, the radius of the cylinder is r, and its height is 2r.

The volume of a sphere is given by the formula, V = (4/3)πr³, where V is its volume, and r is its radius.

Thus, the volume of the given sphere using the formula is (4/3)πr³.

The volume of a cylinder is given by the formula, V = πr²h, where V is its volume, r is its radius, and h is its height.

Thus, the volume of the given cylinder using the formula is πr²(2r) = 2πr³.

Now, to compare the two volumes we take their ratios, as

Volume of the sphere/Volume of the cylinder

= {(4/3)πr³}/{2πr³}

= 2/3.

Thus, the volume of the sphere/the volume of the cylinder = 2/3,

or, the volume of the sphere = (2/3)*the volume of the cylinder.

Given the volume of the cylinder to be 54 m³, Amie should have multiplied 54 by 2/3 instead of adding the two.

Thus, Amie's error while measuring the volume of a sphere is that Amie should have multiplied 54 by 2/3. Thus, the first option is the right choice.

Learn more about volumes at

brainly.com/question/12398192

#SPJ4

For the complete question, refer to the attachment.

6 0

2 years ago

Find the area of the shape below.

m_a_m_a [10]

Answer:

$A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2$

Step-by-step explanation:

I assume that it is a composed figure formed by a triangle and a square.Since you did not give the dimensions of the triangle and the dimensions of the square, I will giveyou a general explanation about how to solve this exercise.

The area of the shape will be the sum of the the area of the square and the area of the triangle.

Then, you need to remember that the area of a triangle can be calculated with the following formula:

$A_{triangle}=\frac{bh}{2}$

Where "b" is the base and "h" is the height.

And the area of a square can be found with this formula:

$A_{square}=s^2$

Where "s" is the length of any side of the square.

Therefore, the area of the shape will be

$A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2$

3 0

3 years ago

Solve A=LW for width

Nataly_w [17]

Area= (length)(width)

divide by (length) on both sides.

(width)= (area)/(length).

Your best bet is treating area, length, and width as numbers. You can plug in numbers and take them out in the end. Hope this helps!

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3 years ago

X÷79 + 72 - 18 hellppppp

tino4ka555 [31]

Answer:

1/5688x-18

I am not sure about my answer because I think the question is missing some information but my answer is 1/5688x-18. Thanks!

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3 years ago