What is the distance, d, between the points (3,5/2) and (5/3,1)?
1 answer:
You might be interested in
Answer:
5.33
Step-by-step explanation:
move the 4 out of the summation because just a constant multiplier
4 *sum from 1 to 10 for (1/4)^(n-1) [sorry i don't know how to write sums using latex)
The formula for the geometric sum is :
First term*(1-multiplier^n)/(1-multiplier), formally
Here multiplier is 1/4
First term is (1/4)^(1-1) = 1
Thus the value of sum is which equals
We factored out 4 so its which is
This equals 5.333328247 which is 5.33 to the nearest hundredth