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Alecsey [184]
4 years ago
9

Determine the pH at the equivalence (stoichiometric) point in the titration of 27 mL of 0.24 M C6H5SH(aq) with 0.22 M NaOH(aq).

The Ka of thiophenol is 3.2 x 10-7.
Chemistry
1 answer:
Zinaida [17]4 years ago
7 0

Answer:

6.5 slightly acidic

Explanation:

pH =pka   -  log  [acid] / [base]

pH =6.49   -   log[0.224]/[0.22]

6.59-0.0377

6.45.

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Ionic compounds are formed from ionic bonds, whereby an electron is transferred from the metal cation to the nonmetal anion. Ion
Karolina [17]

Answer:

NaI

Explanation:

In I₂, HI and IBr, both atoms are nonmetals and they form covalent bonds in which electrons are shared.

In NaI, Na is a metal and I a nonmetal, so they form an ionic bond, where Na loses an electron to form Na⁺ and I gains an electron to form I⁻.  Anions and cations are attracted to each other through electrostatic forces.

Since ionic bonds are stronger than covalent bonds, more energy is required to break them in the melting process, thus having higher melting points.

All in all, NaI is the one with the highest melting point.

7 0
4 years ago
A 26-week-old baby was brought to the pediatric clinic because of increasing lethargy and cyanosis. The infant has been in good
Elena-2011 [213]

Answer:

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Explanation:

3 0
3 years ago
A home solar energy storage unit uses 4.75 ✕ 102 L of water for storing energy. On a sunny day, the water absorbed 2.75 ✕ 104 kJ
Sav [38]

Answer : The water's temperature change will be, 13.85^oC

Explanation : Given,

Density of water = 0.998 g/mL

Volume of water = 4.75\times 10^2L=4.75\times 10^5mL

(conversion used : 1 L = 1000 mL)

Specific heat of water = 4.184J/g^oC

Heat absorbed = 2.75\times 10^4kJ=2.75\times 10^7J

(conversion used : 1 kJ = 1000 J)

First we have to determine the mass of water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

\text{Mass of water}=(0.998g/mL)\times (4.75\times 10^5mL)=474050g

Now we have to calculate the change in temperature of water.

Formula used :

Q=m\times C_w\times \Delta T

where,

Q = heat absorbed by water

m = mass of water

C_w = specific heat of water

\Delta T = change in temperature

Now put all the given value in the above formula, we get:

2.75\times 10^7J=474050g\times 4.184J/g^oC\times \Delta T

\Delta T=13.85^oC

Therefore, the water's temperature change will be, 13.85^oC

8 0
4 years ago
What is the pH of 500 mL of water after the addition of 1 mL of 2M NaOH?
Fudgin [204]

Answer:

pH = 11.60

Explanation:

When we add a base, we are increasing [OH⁻], so the pH will be totally basic.

pH of water = 7

Basic pH > 7

We are adding 2 M . 1 mL = 2 mmoles

2 mmoles of OH⁻ are contained in 501 mL of total volume.

[OH⁻] = 2 mmol / 501 mL =  3.99×10⁻³ M

- log 3.99×10⁻³ M = 2.39 → pOH

pH = 14 - pOH → 11.61

Water equilibrium

2H₂O  ⇄  H₃O⁺   +  OH⁻          Kw = 1×10⁻¹⁴

NaOH  →  Na⁺   +  OH⁻

8 0
3 years ago
Barium (Ba) is an alkaline earth metal.<br><br>t or f
tatiyna

Barium is a chemical element with symbol Ba and atomic number 56. It is the fifth element in group 2 and is a soft, silvery alkaline earth metal. Because of its high chemical reactivity, barium is never found in nature as a free element. Thanks and I hope it helped.

8 0
4 years ago
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