Answer:
a) both substances are insoluble in water
b) both substances are soluble in ligroin
c) both substances suffer combustion, octane produces more CO₂ than hexene.
d) both substances are less dense than waterl, with hexene having the lowest density.
e) only hexene would react with bromine
f) only hexene would react with permanganate
Explanation:
a) both substances are non-polar and water is polar
b) both substances are non-polar and lingroin is non-polar
c) C₈H₁₈ + 17.5O₂ → 8CO₂ + 9H₂O
C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O
d) water = 997 kg/m³
ocatne = 703 kg/m³
hexene = 673 kg/m³
e) bromine test is used to detect unsaturations
f) permanganate test is used to detect unsaturations
I’m pretty sure it would be B
Crustal deformation builds landforms when two tectonic plates start to push into each other they can rise up and build mountains, or when they sink under, they create valleys.
<h3>How crustal deformation builds landforms?</h3>
Tectonic pressure in a crust can cause folding. Folding can end up with the formation of valleys and mountains so we can conclude that when two tectonic plates start to push into each other they can rise up and build mountains, or when they sink under, they create deep valleys.
Learn more about plates here: brainly.com/question/16939139
Let us write succinic acids as H2Suc
The first ionization is
H2Suc ----> HSuc- + H+
The seond ionization is
HSuc- ----> Suc-2 + H+
Calculate the H+ concentration of from the first ionization using pKa1.
Then, calculate the H+ concentration from the second ionization using pKa2.
Next, use the buffer equation to calculate the concentration of the salt in the solution. Then, use the given volume to get the number of moles of the salt. Finally, use the given molecular weight to get the mass.
Hello,
I believe this is (25 g Al) * (1 mol H / 1.008 g H) = 24.8015 mol H
Hopefully that was the right approach.
I thought that if one mole of Al is
26.982 g, then the numbers of moles for H (1.008 g/mol) would be about 25 mol.
If it doesn’t make sense or if you have resources/notes to which I can refer, I’ll see what I can do!
Good luck!
