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Wewaii [24]
3 years ago
13

Can you solve this and show work please

Mathematics
1 answer:
Alona [7]3 years ago
7 0
It is hard for me sorry so sorry
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Which of the following functions are homomorphisms?
Vikentia [17]
Part A:

Given f:Z \rightarrow Z, defined by f(x)=-x

f(x+y)=-(x+y)=-x-y \\  \\ f(x)+f(y)=-x+(-y)=-x-y

but

f(xy)=-xy \\  \\ f(x)\cdot f(y)=-x\cdot-y=xy

Since, f(xy) ≠ f(x)f(y)

Therefore, the function is not a homomorphism.



Part B:

Given f:Z_2 \rightarrow Z_2, defined by f(x)=-x

Note that in Z_2, -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular f(x)=x

f(x+y)=x+y \\  \\ f(x)+f(y)=x+y

and

f(xy)=xy \\  \\ f(x)\cdot f(y)=xy

Therefore, the function is a homomorphism.



Part C:

Given g:Q\rightarrow Q, defined by g(x)= \frac{1}{x^2+1}

g(x+y)= \frac{1}{(x+y)^2+1} = \frac{1}{x^2+2xy+y^2+1}  \\  \\ g(x)+g(y)= \frac{1}{x^2+1} + \frac{1}{y^2+1} = \frac{y^2+1+x^2+1}{(x^2+1)(y^2+1)} = \frac{x^2+y^2+2}{x^2y^2+x^2+y^2+1}

Since, f(x+y) ≠ f(x) + f(y), therefore, the function is not a homomorphism.



Part D:

Given h:R\rightarrow M(R), defined by h(a)=  \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)

h(a+b)= \left(\begin{array}{cc}-(a+b)&0\\a+b&0\end{array}\right)= \left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right) \\  \\ h(a)+h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)+ \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)=\left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right)

but

h(ab)= \left(\begin{array}{cc}-ab&0\\ab&0\end{array}\right) \\  \\ h(a)\cdot h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)\cdot \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)= \left(\begin{array}{cc}ab&0\\-ab&0\end{array}\right)

Since, h(ab) ≠ h(a)h(b), therefore, the funtion is not a homomorphism.



Part E:

Given f:Z_{12}\rightarrow Z_4, defined by \left([x_{12}]\right)=[x_4], where [u_n] denotes the lass of the integer u in Z_n.

Then, for any [a_{12}],[b_{12}]\in Z_{12}, we have

f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\  \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)

and

f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)

Therefore, the function is a homomorphism.
7 0
3 years ago
Why is 186,426 divisible by 3 and 9
Zepler [3.9K]
The divisibility rule
For example
The divisibility rule for three is adding the number together
1+8+6+4+2+6= 27
And 3 is divisible by 27
And for nine
It’s similar to three
7 0
3 years ago
Car A travels at 35 miles per hour and Car B travels at a greater speed of x miles per hour. Choose the expression that represen
Rina8888 [55]

Answer:

-2x+25 D

Step-by-step explanation:

To determine how far it will go in an unspecified number of hours, we can let t = time in hours. The letter t will be our variable. Assuming that the car travels at the same speed, we can state that the rate is 55, and that will be our constant. The expression would then be:

Distance of car traveled in t hours, which we can denote as D(t) = 55 x t = 55t

This means that D is a function of t, and D represents the total distance traveled in t hours.

8 0
2 years ago
Read 2 more answers
Help asap pleasee, I'LL GIVE BRAINLIEST FOR THIS QUESTION
pochemuha

Answer:

C is the answer

Step-by-step explanation:

2π/2 = π

8 0
2 years ago
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What is the area, in square centimeters, of the figure shown.
aev [14]
The area including cutout is 15*8=120
the area of cutout is 5*5=25

120-25=95 cm²
8 0
3 years ago
Read 2 more answers
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