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3 years ago

Define relative density

Physics

2 answers:

julia-pushkina [17]3 years ago

8 0

Relative density is the ratio of the density of a substance to the density of a standard substance like water or air.

egoroff_w [7]3 years ago

3 0

Hello There!

Relative density is another word for specific gravity. Relative density is comparing the density of one thing to the density of another. Most of the time, you look at the density of water so we look at the density of an object relative to the density of water.

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one of the lady spartans was falling to the ground after dunking the winning basket. At the end of her fall, she was falling 4 m

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3 years ago

Two electrodes, separated by a distance d, in a vacuum are maintained at a constant potential difference. An electron, accelerat

Alja [10]

Answer:

Explanation:

Given that, the distance between the electrode is d.

The electron kinetic energy is Ek when the electrode are at distance "d" apart.

So, we want to find the K.E when that are at d/3 distance apart.

K.E = ½mv²

Note: the mass doesn't change, it is only the velocity that change.

Also,

K.E = Work done by the electron

K.E = F × d

K.E = W = ma × d

Let assume that if is constant acceleration

Then, m and a is constant,

Then,

K.E is directly proportional to d

So, as d increase K.E increase and as d decreases K.E decreases.

So,

K.E_1 / d_1 = K.E_2 / d_2

K.E_1 = E_k

d_1 = d

d_2 = d/3

K.E_2 = K.E_1 / d_1 × d_2

K.E_2 = E_k × ⅓d / d

Then,

K.E_2 = ⅓E_k

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7 0

3 years ago

The electric field in the region between the plates of a parallel plate capacitor has a magnitude of 6.3 105 V/m. If the plate s

xz_007 [3.2K]

Answer:

3.528×10² V.

Explanation:

potential difference: This is the work done when one coulomb of charge moves from one point to another in an electric field. The S.I unit of potential difference is volt. The formula of potential difference is given as,

V = kq/r..................... Equation 1

And

E = kq/r² .................. Equation 2

Comparing equation 1 and equation 2,

V = E×r............................. Equation 3

Where V = potential difference, E = Electric field between the plate of the capacitor, r = distance between the plate.

Given: E = 6.3×10⁵ V/m, r = 0.56 mm = 0.00056 m.

Substitute into equation 3,

V = 6.3×10⁵×0.00056

V = 3.528×10² V.

Hence the potential difference of the plate = 3.528×10² V.

4 0

3 years ago