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slava [35]
3 years ago
9

If a person (weighs 70kg) jumped of a moving car (at 100km/h) and fell on asphalt what is the amount of force applyied to his bo

dy that touches the ground first? What are the chancese of dying if the only impact to the body is from the ground?
Physics
1 answer:
jok3333 [9.3K]3 years ago
6 0

Answer:

The amount of force applied to his body is 1944.44 N

<em>The chances of the person dying is very high owing to the high impact force with which the person would experience when he or she lands on the asphalt road due to the jump out of the moving car.</em>

Explanation:

We all know that,

F = Ma where,

F = Force

M = weight of the person

a = acceleration or velocity of the moving car

Therefore;

F = { 70 x (100 x 1000) } / [3600]

= [7 000 000] / 3600

= <u>1944.44 N</u>

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Explanation:

First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:

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Substituting,

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