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natulia [17]
2 years ago
11

Cylinder A has a mass of 2kg and cylinder B has a mass of 10kg. Determinethe velocity of A after it has displaced 2m from its or

iginal starting position. Neglect the mass of the cable and pulleys and assume that both cylinders start at res
Physics
1 answer:
Marta_Voda [28]2 years ago
5 0

The velocity of A is 5.16m/s²

<u>Explanation:</u>

Given-

mass of cylinder A, mₐ = 2kg

mass of cylinder B, mb = 10kg

Distance, s = 2m

Velocity of A, v = ?

Let acceleration due to gravity, g = 10m/s²

We know,

a = \frac{mb * g - ma * g}{ma + mb} \\\\a = \frac{10 * 10 - 2 * 10}{ 2 + 10} \\\\a = \frac{80}{12} \\\\a = 6.67m/s^2

We know,

v = \sqrt{2as}

v = \sqrt{2 X 6.67 X 2} \\\\v = \sqrt{26.68} \\\\v = 5.16m/s^2

Therefore, the velocity of A is 5.16m/s²

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A 3.0 kg rifle is held firmly by a 50.0 kg woman, initially standing still. A 0.06 kg bullet leaves the rifle muzzle with a velo
ohaa [14]

Answer:

48kg

Explanation:

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7 0
2 years ago
If in 30 mins Alex runs to a store that is 4 km away, what is her average speed in km/h
masha68 [24]
15 km 30 divided by 4 is 7.5 km in 30 min times that by 2 the answer is 15
6 0
3 years ago
An object is originally moving at a constant velocity of 8 m/s in the -x direction. It moves at this constant velocity for 3 sec
aivan3 [116]

Answer:

244.64m

Explanation:

First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:

x = V*t = -8\frac{m}{s} *3s = -24m

After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:

1. The velocity will start to decrease untill it reaches 0m/s.

2. Then, the velocity will start to increase at the rate of the acceleration.

The distance that the ball travels in the first phase can be found with the following expression:

v^2 = v_0^2 + 2a*d

Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:

d = \frac{v^2 - v_0^2}{2a} = \frac{(0m/s)^2 - (-8m/s)^2}{2*7m/s^2}= -4.57m

Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:

t_1 = \frac{v}{a} = \frac{8m/s}{7m/s^2} = 1.143 s

Then, the time of the second phase will be:

t_2 = 9s - t_1 = 9s - 1.143s = 7.857s

Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:

x = \frac{1}{2}a*t^2 + v_0*t + x_0

V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:

x = \frac{1}{2}*7\frac{m}{s^2}*t^2 + 0m/s*t + 0m = 216.07m

So, the total distance covered by this object in meters will be the sum of all the distances we found:

x_total = 24m + 4.57m + 216.07m = 244.64m

8 0
2 years ago
Frost wedging happens when _____.
KiRa [710]

Answer: water freezes inside a rock, causing it to break

Weathering is a natural process in which the rocks break into pieces or sediments by the action of wind, water and chemical agents. Frost wedging is a physical weathering process. It occurs in an area where temperature fluctuations occurs due to change in the climatic conditions. This occurs due to rapid heating and cooling. The rocks lying in a cold environment, the water residing in the rocks gets freezed. The water in ice form that is solid form acquire more space than in liquid form, therefore, the developed ice will affect the physical structure of the rock. The formation of ice results in the development of break or crack in the rock typically in the shape of a wedge and thus the phenomena is called as frost wedging.

Hence, frost wedging happens when water freezes inside a rock, causing it to break.

8 0
3 years ago
Mass is the weight of an object
o-na [289]

Answer:

Mass is the amount of matter in a object.

Explanation:

3 0
3 years ago
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