3 years ago

The area of a square is defined by, A(x) = x 2 - 8x + 16. What is the length of a side of the square?

1 answer:

4 0

You must factor the second-degree polynomial to find the sides of the square. The correct factorization for this case is
x ^ 2 - 8x + 16 = (x-4) (x-4).
Therefore, the length of the side of the square is
L = (x-4).

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2. There were 35 children and 10 adults at a cookout.

qwelly [4]

Answer:

a.2:7

b.7:9

c.4:5

hope it helps

Explanation -

a. as original ratio is 10/35 , we reduce it to 2:7.

b. as original ratio is 35/45 , we reduce it to 7:9

c. as original ratio is 40:50 , we reduce it to 4:5

5 0

3 years ago

What is the difference in simplest form? <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%5E2%2B3n%2B2%7D%7Bn%5E2%2B6n%2B8%7D-%5

Paha777 [63]

$\bf \cfrac{n^2+3n+2}{n^2+6n+8}-\cfrac{2n}{n+4}\implies \cfrac{n^2+3n+21}{(n+4)(n+2)}-\cfrac{2n}{n+4}
\\\\\\
\textit{so our LCD will just be (n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(n+2)(2n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(2n^2+4n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~2n^2-4n}{(n+4)(n+2)}
\implies 
\cfrac{-n^2-n+2}{(n+4)(n+2)}
\\\\\\
\cfrac{-(n^2+n-2)}{(n+4)(n+2)}\implies \cfrac{-\underline{(n+2)}(n-1)}{(n+4)\underline{(n+2)}}\implies \cfrac{-(n-1)}{n+4}\implies \cfrac{1+n}{n+4}$