For this case we have the following expression:
We must indicate the first step that allows to start the simplification of the expression.
It is observed that the first step to follow is to solve the square of the binomial that is in the numerator of the expression.
Answer:
Option A
<span>There are 56 possible combinations when drawing two chips. Remember that you cannot draw two of the same chips from the bag, so 11, 22, 33, 44, 55, 66, 77, and 88 are not possible. Therefore, 20 of 56 combinations are divisible by 3, or approximately 36 percent.
12,13,14,15,16,17,18
21,23,24,25,26,27,28
31,32,34,35,36,37,38
41,42,43,45,46,47,48
51,52,53,54,56,57,58
61,62,63,64,65,67,68
71,72,73,74,75,76,78
81,82,83,84,85,86,87</span>
2x + 5 3x + 5 x + 1
--------------- - ----------------- - -------------------
x(x - 3) x (x+3)(x-3) (x +3)(x - 3)
(x + 3) (2x + 5) - (3x + 5) - x ( x + 1)
= ---------------------------------------------------------
x (x+3)(x-3)
2x^2 +6x +5x + 15 -3x - 5 -x^2 - x
= -----------------------------------------------
x (x+3)(x-3)
x^2 + 7x + 10
= --------------------
x (x+3)(x-3)
(x +5)(x+2)
= --------------------
x (x+3)(x-3)
or
(x +5)(x+2)
= --------------------
x^3 - 9
answer is A. first one
