All categories

3 years ago

Find the area of this shape below

Mathematics

1 answer:

rjkz [21]3 years ago

6 0

Answer: 28

Step-by-step explanation:

2 × 8 = 16

8 + 4 = 12

12 ÷ 2 = 6

6 × 2 = 12

16 + 12 = 28

You might be interested in

If 4 electricians can wire some new houses in 20 days, how many electricians would be required to do the job in 10 days?

abruzzese [7]

Answer:

Step-by-step explanation:

20/2 = 10

4/2 = 2

8 0

2 years ago

Solve the system linear equations, using Gaussian Elimination

otez555 [7]

Just look it up on the web that will help a lot

5 0

3 years ago

Solve<br> 2x − 4y = 2<br> y = 4

liberstina [14]

Point Form:

( 9 , 4 )

Equation Form:

x = 9 , y= 4

7 0

3 years ago

Read 2 more answers

A linear relationship with a slope of 2 and a<br> y-intercept of 3

qwelly [4]

Answer:

The linear relationship is represented by y = 2x + 3.

Step-by-step explanation:

We are given a y-intercept of an equation as well as a slope:

slope = 2
y-intercept = 3

We can use this information and substitute it into the slope-intercept form equation to get our linear relationship:

y = mx + b

In this formula, m is our slope and b is our y-intercept.

Therefore:

m = 2
b = 3

Finally, let us substitute these into the equation:

$y = 2x + 3$

This is our final equation.

4 0

3 years ago

Read 2 more answers

Evaluate the surface integral. s y ds, s is the helicoid with vector equation r(u, v) = u cos(v), u sin(v), v , 0 ≤ u ≤ 6, 0 ≤ v

Juliette [100K]

Compute the surface element:

$\mathrm dS=\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv$

$\vec r(u,v)=(u\cos v,u\sin v,v)\implies\begin{cases}\vec r_u=(\cos v,\sin v,0)\\\vec r_v=(-u\sin v,u\cos v,1)\end{cases}$

$\|\vec r_u\times\vec r_v\|=\sqrt{\sin^2v+(-\cos v)^2+u^2}=\sqrt{1+u^2}$

So the integral is

$\displaystyle\iint_Sy\,\mathrm dS=\int_0^\pi\int_0^6u\sin v\sqrt{1+u^2}\,\mathrm du\,\mathrm dv$

$=\displaystyle\left(\int_0^\pi\sin v\,\mathrm dv\right)\left(\int_0^6u\sqrt{1+u^2}\,\mathrm du\right)$

$=\dfrac23(37^{3/2}-1)$

4 0

3 years ago