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vaieri [72.5K]
3 years ago
15

Use a while loop to determine how many terms in the series 3k^2 are required for the sum to surpass 2000

Mathematics
2 answers:
Bumek [7]3 years ago
6 0
Using JAVA:
int sum = 0;       
int k = 1;       
while(sum  <= 2000) {           
sum += 3*k*k;           
 k++;       
 }               
System.out.println(k);

Output: 14

Which means it will take 14 terms for the series to surpass 2000


neonofarm [45]3 years ago
4 0
I am assuming k starts at 0. Python code (or pseudocode) would be this:
-------------------------------
S = 0
count_term = 0
k = 0
while S <= 2000:     S = S + 3*k**2
    count_term = count_term + 1     k = k + 1

print(count_term)
-------------------------------

It will print 14

If k should start at other number then just replace number at third line and execute it.
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-2 4/5 + 1/4 equals what ?
vlada-n [284]
Hey there! :)

Since 2 4/5 is greater than 1/4, the answer is negative.

You can just subtract 2 4/5 and 1/4 and add the (-) sign

2 4/5 - 1/4

Change the fractions so they can have a common denominator: 20

2 4/5 = 2 16/20

1/4 = 5/20

2 16/20 - 5/20 = 2 11/20

Add the (-) sign → -2 11/20

Answer ⇒ -2 11/20

:)
5 0
2 years ago
1. Suppose you have a variable X~N(8, 1.5). What is the probability that you have values between (6.5, 9.5)
Natalija [7]

Answer:

0.6826 = 68.26% probability that you have values in this interval.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that \mu = 8, \sigma = 1.5

What is the probability that you have values between (6.5, 9.5)?

This is the p-value of Z when X = 9.5 subtracted by the p-value of Z when X = 6.5. So

X = 9.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.5 - 8}{1.5}

Z = 1

Z = 1 has a p-value of 0.8413.

X = 6.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.5 - 8}{1.5}

Z = -1

Z = -1 has a p-value of 0.1587

0.8413 - 0.1587 = 0.6826

0.6826 = 68.26% probability that you have values in this interval.

7 0
2 years ago
Find the value of: (ii) [(1/4) -1 + (1/3) -2 - (1/2) -3 ] ÷ 5
Anastaziya [24]

Answer:

-71/6

Step-by-step explanation:

[(1/4) -1 + (1/3) -2 - (1/2) -3 ] ÷ 5

[(3/12)-(12/12)+(4/12)-(24/12)-(6/12)-(36/12)] ÷ 5

[-71/12]/5

-71/60

6 0
3 years ago
PLEASE HELPPP kahsjahsjad I need help
Klio2033 [76]

Answer:

166\frac{2}{3} *x=y

Step-by-step explanation:

\frac{500}{3} =166\frac{2}{3}

Therefore, 166\frac{2}{3} *x=y

7 0
2 years ago
18. Find the length of the segment indicated. Round your answer to the
Anon25 [30]

Answer:

B. 6.2

Step-by-step explanation:

x =√18.2²-17.1² =√331.24- 292.41

= √38.83 = 6.2

7 0
3 years ago
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