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BlackZzzverrR [31]
3 years ago
7

18.There is no battery in this simulation. Move the magnet with the N pole toward the loops (coils) connected to the light bulb

until the N pole barely passes the loops. What happens to the light bulb? (2 points)
Mathematics
1 answer:
astraxan [27]3 years ago
7 0

Answer:

Step-by-step explanation:

Whenever a magnetic field linked to loop changes, the current is induced in the loop which sequentially opposes the cause of change in magnetic flux. So whenever the magnet moves towards and away from the loop then it causes the current to induce in the loop to oppose the change in magnetic flux by effectively creating a similar pole that is coming towards the loop.

For example, if the magnet north pole is coming towards loops then it effectively creates a north pole in front of the magnet.

So flow of current will glow the light bulb.

               

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BartSMP [9]
The party was 5 hours. 353.86-200.51=153.35 then you divide that number by 30.67 and you get 5.
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Divide the polynomial x^3+x^2-2x+3 by (x-1)​
Anni [7]

Answer:

x² + 2x + (3 / (x − 1))

Step-by-step explanation:

Start by setting up the division:

.........____________

x − 1 | x³ + x² − 2x + 3

Start with the first term, x³.  Divided by x, that's x².  So:

.........____x²______

x − 1 | x³ + x² − 2x + 3

Multiply x − 1 by x², subtract the result, and drop down the next term:

.........____x²______

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

Repeat the process over again.  First term is 2x².  Divided by x is 2x.  So:

.........____x² + 2x __

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

Multiply, subtract the result, and drop down the next term:

.........____x² + 2x __

x − 1 | x³ + x² − 2x + 3

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...........----------

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.................-(2x² − 2x)

.................---------------

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x doesn't divide into 3, so that's the remainder.

Therefore, the answer is:

x² + 2x + (3 / (x − 1))

8 0
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A box of pencils is 5 1/4 inches wide. Seven pencils, laid side by side, take up 2 5/8 inches of the width. How many inches of t
Andre45 [30]

Answer:   Width of box is not taken up by pencils =  2\dfrac58\text{ inches}

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Step-by-step explanation:

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Width of box is not taken up by pencils =  Width of pencil box  - Width of seven pencils

\left \{ {{y=2} \atop {x=2}} \right. \dfrac{21}{4}-\dfrac{21}{8}\\\\=\dfrac{21\times2-21}{8}\\\\=\dfrac{21}{8}\text{ inches}=2\dfrac58\text{ inches}

Width of box is not taken up by pencils =  2\dfrac58\text{ inches}

Width of each pencil = (Width of seven pencils ) ÷ 7

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Width of each pencil =\dfrac38\text{ inches}

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