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ella [17]
3 years ago
14

Fraction | decimals|percent | 58%

Mathematics
2 answers:
andrey2020 [161]3 years ago
6 0
.58 is 58% in decimal form
kkurt [141]3 years ago
6 0
58/100 is the answer of the quesion
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The formula for computing compound interest for a principal P that is invested at an annual rate r and compounded annually is gi
maria [59]

9514 1404 393

Answer:

  • r ≈ 6%

Step-by-step explanation:

Solving for r when n=2, we have ...

  A=P(1+r)^2\\\\\dfrac{A}{P}=(1+r)^2\\\\\sqrt{\dfrac{A}{P}}=1+r\\\\\boxed{r=\sqrt{\dfrac{A}{P}}-1}

For the given values of A and P, the value of r is ...

  r=\sqrt{\dfrac{5600}{5000}}-1=\sqrt{1.12}-1\approx 1.0583-1\\\\\boxed{r\approx 6\%}

8 0
3 years ago
Jim Tree will drive from his home in Jackson Heights to Jones City. The distance on the map measures 3 1/2 inches. The scale on
expeople1 [14]
Just multiply !!

so 1 inch = 5 miles
3.5 inch must be 3.5×5 = 17.5 miles

so the answer is 17.5 miles !!
7 0
3 years ago
Read 2 more answers
A dog has three puppies. Spot weighs 12 ounces. Rascal weighs 9.5 ounces. Socks weighs 10.2 ounces. What is the total weight of
mario62 [17]

Answer:

c. 32 ounces

Step-by-step explanation:

Given that:

The weight of the Spot = 12 ounces

The weight of Rascal = 9.5 ounces;  &

The weight of Socks = 10.2 ounces.

To find the litters' total weight, we will sum all the given number of the puppies.

i.e. Total weight of the litter = (12 + 9.5 + 10.2) ounces

Total weight of the litter = 31.7 ounces

Total weight of the litter \simeq 32 ounces to the correct number of significant figures.

4 0
3 years ago
3. Janet is flying a kite on a string that is 75m long. The kite is 62m above the ground. Estimate the distance between Janet an
konstantin123 [22]
Answer: a) It will be a right triangle with a hypotenuse of 75 and a vertical leg that is 62. 
b) The length of the kite string is 75 (given in the problem). However, I believe you are looking for the distance from the spot on the ground beneath the kite to Janet. That is about 42.2 m.

To find the missing distance in the right triangle. You have to use the Pythagorean Theorem.  I set it up and solve it below.

a^2 + b^2 = c^2
x^2 + 62^2 = 75^2
x^2 + 3844 = 5625
x^2 = 1781
x = 42.2 (about)

3 0
3 years ago
"if f(x)=x+1/x then the set of values for which f increases is"
Anettt [7]
The solution for this problem would be:
f'(x) = 1 - 1/x^2 = (x^2 - 1)/x^2 
is positive where |x| > 1 
hence (-inf, -1) and (1, inf) are the regions in which f' is positive and therefore f is increasing.
Therefore, the answer is (-infinity,-1] U [1,infinity).
4 0
3 years ago
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