two boys decided to buy a computer. The second boy had 5/6 of the amount of money the first had. The first boy had 7/8 of the pr
ice of the computer. Together they had $696 more than they needed to pay. What was the price of the computer
1 answer:
Answer:
1152$
Step-by-step explanation:
b1 = 7/8 C
b2 = 5/6 b1 = 35/ 48 C
7/8 C + 35/48 C = C + 696
42/48 C + 35/48 C = 48/48 C + 696 * 48/48
(42 + 35 - 48 ) C = 696 * 48
29 C = 33408
C =1152.
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