Answer:
<u><em>Steven is 15 and one half years old now</em></u>
Step-by-step explanation:
<u />
Linear equations
Sometimes we need to know the value of a variable in a given equation and that variable is given as a polynomial of degree 1. Solving for that variable means isolating it and replacing the other known values
Steven was 7 years old eight and one-half years ago. If we call x as the actual age of Steven, his age eight and one-half years ago was

We know he was 7 years old then, so

We need to know his actual age, so let's solve for x, adding
to each side of the equation

Simplifying

Steven is 15 and one half years old now
Daddy daddy daddy daddy and daddy
Let;
A(-8,6) B(6,6) C(6, -4) D(-8, -4)
Let's find the length AB
x₁= -8 y₁=6 x₂=6 y₂=6
We will use the distance formula;
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
![=\sqrt[]{(6+8)^2+(6-6)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%286%2B8%29%5E2%2B%286-6%29%5E2%7D)
![=\sqrt[]{14^2+0}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B14%5E2%2B0%7D)

Next, we will find the width BC
B(6,6) C(6, -4)
x₁= 6 y₁=6 x₂=6 y₂=-4
substitute into the distance formula;
![d=\sqrt[]{(6-6)^2+(-4-6)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%286-6%29%5E2%2B%28-4-6%29%5E2%7D)
![=\sqrt[]{(-10)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%28-10%29%5E2%7D)
![=\sqrt[]{100}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B100%7D)

Area = l x w
= 14 x 10
= 140 square units
Given:
The function is

To find:
The zeros of the given function.
Solution:
The general form of polynomial is
...(i)
where, a is a constant,
are zeros of respective multiplicities
.
We have,

On comparing this with (i), we get


It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.
Therefore, the correct option is B.
Answer:
The answer is y = 3(4)^x or answer choice C