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4 years ago

Evaluate the following expression when x = 4 and y = 5:

Mathematics

2 answers:

marissa [1.9K]4 years ago

8 0

It would be 23.5 idk if your aloud to do that
or 141/6

antiseptic1488 [7]4 years ago

3 0

Hello!

You plug the values in for x and y

x = 4
y = 5

$\frac{ 4^{2}+ 5^{3} }{2 + 4}$

Combine like terms

$\frac{16 + 125}{6}$

Add

$\frac{141}{6}$

Divide

The answer is 23.5

Hope this helps!

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If you call your random variable $X$ , then what you are looking for is

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We need a table with of the normal distribution. But we can only find the table with $\mu = 0$ and $\sigma = 1$ . Because of that, first we need to normalize our random variable:

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(you can always normalize your variable following the same formula!)

now we can do something similar to our limits, to get a better expression:

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And we transform our problem to a simpler one:

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(see Figure 1)

From our table we can see that $P(Z \leq 1.2) = 0.8849$ (this is represented in figure 2).

Remember that the whole area below the curve is exactly 1. So we can conclude that $P(Z \geq 1.2) = 0.1151$ (because 0.8849 + 0.1151 = 1). We also know the normal distribution is symmetric, then