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2 years ago

What number r missing 77,73,69,65

Mathematics

2 answers:

Ad libitum [116K]2 years ago

8 0

81,85,89 are the missing numbers

Gnesinka [82]2 years ago

5 0

Answer:

Step-by-step explanation:

All the numbers are odd and have a difference of two between the next term.

Therefore, the answer can be found by adding 2 to 65 or subtracting two from 69.

Hopefully this helps!

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Sorry guys but I don't understand please help me

Elan Coil [88]

Look at the denominators. The second fraction's denominator is 3 times the first fraction's denominator. Since the fractions are equal, it means you have to multiply the first fraction's numerator by 3 too. So, b=9. Good luck!

6 0

2 years ago

Read 2 more answers

HELP PLS :) its for my class

Elis [28]

Answer:

about 170

Step-by-step explanation:

i say thi because 360 into 4 quadrants is 90 per qudrant than tge second quadrant is almost full so i put the answer nearly 2 quadrants

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2 years ago

Which number line shows 1 to 4 divided into fourths?

romanna [79]

Answer:

the second one dose I believe

3 0

2 years ago

Please help!! What is the solution to the quadratic inequality? 6x2≥10+11x

fredd [130]

Answer:

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

Step-by-step explanation:

First of all, let simplify and factorize the resulting polynomial:

$6\cdot x^{2} \geq 10 + 11\cdot x$

$6\cdot x^{2}-11\cdot x -10 \geq 0$

$6\cdot \left(x^{2}-\frac{11}{6}\cdot x -\frac{10}{6} \right)\geq 0$

Roots are found by Quadratic Formula:

$r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}$

$r_{1} = \frac{5}{2}$ and $r_{2} = -\frac{2}{3}$

Then, the factorized form of the inequation is:

$6\cdot \left(x-\frac{5}{2}\right)\cdot \left(x+\frac{2}{3} \right)\geq 0$

By Real Algebra, there are two condition that fulfill the inequation:

a) $x-\frac{5}{2} \geq 0 \,\wedge\,x+\frac{2}{3}\geq 0$

$x \geq \frac{5}{2}\,\wedge\,x \geq-\frac{2}{3}$

$x \geq \frac{5}{2}$

b) $x-\frac{5}{2} \leq 0 \,\wedge\,x+\frac{2}{3}\leq 0$

$x \leq \frac{5}{2}\,\wedge\,x\leq-\frac{2}{3}$

$x\leq -\frac{2}{3}$

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

3 0

3 years ago

I need help with #16. please show an example, i do not get this,

serious [3.7K]

Here's a diagram showing how to combine angles LDA (in red) and angle ADE (in blue). Hopefully it becomes a bit clearer why these two angles add up to line segment LE. Erase the shared segment DA if it helps show LE better.

See attached image below.

3 0

3 years ago

What number r missing 77,73,69,65​

What number r missing 77,73,69,65