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grandymaker [24]
3 years ago
15

Six-four million, one hundred eighty-six thousand, three hundred square miles in standard form

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0

Answer:

64,186,300 square miles

I'm sorry if I misunderstood.

Good luck mate! :)

Please add Brainliest if you'd like, not that it matters.

Remember to try your best every day!

You might be interested in
find three consecutive even integers so that the twice the sum of the second and third is twelve less than six times the first
zysi [14]

n, n + 2, n + 4 - three consecutive even integers

the twice the sum of the second and third: 2[(n + 2) + (n + 4)]

twelve less than six times the first: 6n - 12

The equation:

2[(n + 2) + (n + 4)] = 6n - 12

2(n + 2 + n + 4) = 6n - 12

2(2n + 6) = 6n - 12       <em>use distributive property</em>

(2)(2n) + (2)(6) = 6n - 12

4n + 12 = 6n - 12       <em>subtract 12 from both sides</em>

4n = 6n - 24       <em>subtract 6n from both sides</em>

-2n = -24        <em>divide both sides by (-2)</em>

n = 12

n + 2 = 12 + 2 = 14

n + 4 = 12 + 4 = 16

<h3>Answer: 12, 14, 16</h3>
4 0
3 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
2 years ago
Please help me explain as well. I will give brainliest.
garik1379 [7]

Answer:

Step-by-step explanation:

6 0
3 years ago
Which is an important difference between the five themes and the several
Zolol [24]

Answer:

i did it again i did i did not do did it

4 0
2 years ago
What is the equation of the line with points represented in the table?
EleoNora [17]

Answer:

b,c,f

Step-by-step explanation:

i did the assignment

5 0
2 years ago
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