Answer:
Step-by-step explanation:
y-5=3(x+2)
y-5=3x+6
y-5-6=3x+6-6
y-1=3x
slope = (y2-y1)/(x2-x1)
= (70-52)/(8-1)
= 18/7
=2.6
point slope form
y-y1 = m(x-x1)
y-52 = 2.6(x-1)
distribute
y-52 = 2.6x-2.6
add 52 to each side
y = 2.6x+49.4
y = 2.6x +49
the initial temperature is 49.4 or about 49
and it increases about 2.6 degrees each week
13 factored out is 13x - 39 add 39 to both sides it equals 13x=78 and 78 divided by 13 is 6 the anwser is x=6
Y=2.50x+20. Plug in values for x starting at 0 and you will get values for y and then graph.
To find the area between the x-axis and the parabolic curve, take the integral of the area in which the curve is above the x-axis.
function of the graph is
y = 4x - x²
We can tell by the function (specifically -x²) that the parabola will point downward.
To find the domain in which y>0, let's find the roots (0's) of the function:
0 = 4x - x²
0 = x (4 - x)
x = 0 or x = 4
Between x=0 and x=4, the curve is above the x-axis. To find the area of the graph, let's take the integral on this range:
First, take the antiderivative of 4x - x²:
2x² - (1/3) x³
Then, plug x=4 into the anti-derivative, and subtract the anti-derivative at x=0:
2(4)² - (1/3)(4³) - (0 - 0)
32 - 64/3
96/3 - 64/3 = 32/3
Closest Answer is C) 10
