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Leya [2.2K]
3 years ago
10

How do you solve for the Rations of Special Triangles? This is confusing

Mathematics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

The answer to your question is  x = \frac{3\sqrt{2}}{2}

Step-by-step explanation:

Data

right triangle

x = ?

hypotenuse = 3

To solve this problem use trigonometric functions. The trigonometric function that relates the opposite side and the hypotenuse is sine.

            sin Ф = Opposite side / hypotenuse

-Solve for Opposite side (x)

            x = hypotenuse  sin 45

-Substitution

 sin 45 = \frac{\sqrt{2}}{2}

            x = 3\frac{\sqrt{2}}{2}

-Solution

            x = \frac{3\sqrt{2}}{2}  It is not possible to simplify any more.

           

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