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julia-pushkina [17]

2 years ago

11

2. What is the factored form of 2x^2 + x – 3?

1 answer:

Darya [45]2 years ago

5 0

Answer:

$(2x + 3)(x - 1)$

Step-by-step explanation:

$(2{x}^{2} + 3x) - (2x - 3) \\ x(2x + 3) -1(2x + 3) \\ \\ (x - 1)(2x + 3)$

I am joyous to assist you anytime.

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blagie [28]

Answer:

miles hybrid car went = 9.80 gal × 54.1 miles/gal

= 530.18 miles

132km × 0.621 = 81.972 miles

530.18 miles = 9.80 gal

1 mile = 9.80/530.18

= 0.018 gal

81.972 miles = 0.018 × 81.972

= 1.515 gal

1.515 gal × 3.785 = 5.734 litres

3 0

3 years ago

If 16 counters is 4/9 what is the ONE?

klemol [59]

(4/9)/16 = 4/(9*16) = 4/(4*4*9) = 1/(4*9) = 1/36

One counter is $\frac{1}{36}$ <span> if 16 of them are </span> $\frac{4}{9}$

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2 years ago

What is the separation method of blood?

natita [175]

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2 years ago

Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

$\implies k=\dfrac{19}{6}$

<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

$\implies -3=6.5k$

$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

$\implies 3=9.5k$

$\implies k=\dfrac{6}{19}$

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1 year ago

Gillian earns $7.50 an hour babysitting on the weekends.Last week she babysat for 2.2 hours on Saturday and 3.5 hours on Sunday.

Musya8 [376]

Total hours= 2.2+3.5=5.7

Total earned = 5.7 x $7.50= $42.75

8 0

3 years ago