Answer:
The probability that the insurer pays at least 1.44 on a random loss is 0.18.
Step-by-step explanation:
Let the random variable <em>X</em> represent the losses covered by a flood insurance policy.
The random variable <em>X</em> follows a Uniform distribution with parameters <em>a</em> = 0 and <em>b</em> = 2.
The probability density function of <em>X</em> is:
It is provided, the probability that the insurer pays at least 1.20 on a random loss is 0.30.
That is:
⇒
The deductible d is 0.20.
Compute the probability that the insurer pays at least 1.44 on a random loss as follows:
Thus, the probability that the insurer pays at least 1.44 on a random loss is 0.18.
Answer:
a and b and are he corrct answers
Step-by-step explanation:
Answer:
Choice C is the correct answer.
Step-by-step explanation:
Given expression is
(3p-7)(2p²-3p-4)
we have to find the product of linear expression to quardatic expression.
Firstly, multiply 3p to quardatic expression and -7 to quardatic expression and add.
3p(2p²-3p-4)-7(2p²-3p-4)
Multiply 3p to each term of quardatic expression and -7 to each term of quardatic expression and add all terms:
3p(2p²)+3p(-3p)+3p(-4)-7(2p²)-7(-3p)-7(-4)
6p³-9p²-12p-14p²+21p+28
add like terms
6p³+(-9-14)p²+p(-12+21)+28
6p³-23p²+9p+28 which is the correct answer.
I don’t know the answer to this sorry
Answer:
64 ×
Step-by-step explanation:
(8 × 10³)² = (8 × 10³)(8 × 10³)
= 8 × 10³ × 8 × 10³
= 64 ×