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3 years ago

What is the product of (3p-7)(2p²-3p-4)

Mathematics

1 answer:

garik1379 [7]3 years ago

3 0

Answer:

Choice C is the correct answer.

Step-by-step explanation:

Given expression is

(3p-7)(2p²-3p-4)

we have to find the product of linear expression to quardatic expression.

Firstly, multiply 3p to quardatic expression and -7 to quardatic expression and add.

3p(2p²-3p-4)-7(2p²-3p-4)

Multiply 3p to each term of quardatic expression and -7 to each term of quardatic expression and add all terms:

3p(2p²)+3p(-3p)+3p(-4)-7(2p²)-7(-3p)-7(-4)

6p³-9p²-12p-14p²+21p+28

add like terms

6p³+(-9-14)p²+p(-12+21)+28

6p³-23p²+9p+28 which is the correct answer.

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3 years ago

If you graph y=2x+1 and y=x+1 how many times would the two lines intersect

krok68 [10]

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3 0

3 years ago

A tutor charges $30 for 5 6 of an hour. What is her hourly rate?

uysha [10]

Answer:

The answer is 36

Step-by-step explanation:

30 times 6 equals 180

180 divided by 5 equals 36

answer 36

3 0

3 years ago

Sanjay borrowed 7,000 at a simple interest rate of 3% per year. After a certain number of years he had paid $840 in interest alt

alexgriva [62]

Answer:

It was 4 years.

Step-by-step explanation:

To solve this problem we need to use the appropriate formula for simple interest, which is shown below:

M = C*r*t

Where M is the amount of interest, C is the initial amount of money, r is the rate of interest and t is the time elapsed in years. Applying the data from the problem we have:

840 =7000*0.03*t

840 = 210*t

210*t = 840

t = 840/210

t = 4

It was 4 years.

7 0

3 years ago

Simplify this problem

ikadub [295]

Answer:

$\boxed{ \frac{ \sqrt[3]{ {x}^{11} } }{4} }$

Step-by-step explanation:

$= > \frac{ {x}^{4} }{ \sqrt[3]{64x} } \\ \\ = > \frac{ {x}^{4} }{ {(64x)}^{ \frac{1}{3} } } \\ \\ = > \frac{ {x}^{4} }{ ({64}^{ \frac{1}{3} } )\times ({x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{ ({( {4}^{3} )}^{ \frac{1}{3} }) \times( {x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{ ({4}^{ \cancel{3} \times \frac{1}{ \cancel{3}} } ) \times( {x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{4 {x}^{ \frac{1}{3} } } \\ \\ = > \frac{ {x}^{4 - \frac{1}{3} } }{4} \\ \\ = > \frac{ {x}^{ \frac{12 - 1}{3} } }{4} \\ \\ = > \frac{ {x}^{ \frac{11}{3} } }{4} \\ \\ = > \frac{ \sqrt[3]{ {x}^{11} } }{4}$

7 0

3 years ago