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PilotLPTM [1.2K]
3 years ago
11

(3x-4)-(x-5) pleaseeee help need asap

Mathematics
2 answers:
I am Lyosha [343]3 years ago
6 0

Answer:

I hope this is the answer. 2x+1

IgorLugansk [536]3 years ago
6 0
So here’s how you solve it. Your first step is to remove the brackets, then you collect like terms and then you have the answer

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If 3a-2b= 8 and a+3b=7 what is the value of 4a+b?
Fittoniya [83]
Step 1: Find the value of one variable in terms of the other.

a+3b=7\\a=7-3b

Step 2: Substitute the value you just found for this variable in the other equation.

3a-2b=8\\3(7-3b)-2b=8\\21-9b-2b=8\\21-11b=8\\21=8+11b\\13=11b\\\frac{13}{11}=b\\ b=1\frac{2}{11}

Step 3: Use your new value for the second variable to find the first.

a+3b=7\\a+3(1\frac{2}{11})=7\\a+3\frac{6}{11}=7\\\\a=3\frac{5}{11}

Now that we know the values for a and b we can find the value of 4a+b.

4a+b\\4(3\frac{5}{11})+1\frac{2}{11}\\12+\frac{20}{11}+1\frac{2}{11}\\\\12+1\frac{9}{11}+1\frac{2}{11}\\\\\boxed{15}
6 0
4 years ago
How many points does it take to determine a line?<br><br> A) 0<br> B) 1<br> C) 2<br> D) 3
KengaRu [80]
1 point to determine a line
3 0
3 years ago
Read 2 more answers
Gin Rummy and are holding 10 cards in your hand from a standarddeck of 52 cards. Find the probability t
zepelin [54]

Here is the correct question

Gin Rummy and are holding 10 cards in your hand from a standard deck of 52 cards.

a) How many ways can you select three kings and four 6's from the deck, the remaining cards not kings or 6's

b) Find the probability that three kings and four 6's are being held by you from the deck.

Answer:

a) 52976

b) \mathbf{3.34866744 \times 10^{-6}}

Step-by-step explanation:

So from the information above,

no of ways three kings can be selected and four 6's from the deck without the remaining cards being kings or 6's can be expressed as:

no of ways to select 3 kings from 4 kings is (^4_3)

no of ways to select 4 6's from (4 6's) is (^4_4)

no of ways to select the remaining 3 cards from (52 - 4 - 4) = 44 cards is (^{44}_3)

Mathematically, multiplying the three together we have:

= (^4_3) (^4_4) (^{44}_3)

= \dfrac{4!}{3!(4-3)!}   \times \dfrac{4!}{4!(4-4)!} \times \dfrac{44!}{3!(44-3)!}

= 4  \times 1 \times 13244

= 52976

To find the probability that you are holding three kings and four 6's from the deck, the remaining cards not kings or 6's can be calculated as follows;

To do this, we need to first know the no of ways we can  select 10 cards out of the pack of 52 cards

i.e

(^{52}_{10})

= \dfrac{52!}{10!(52-10)!}

= \dfrac{52!}{10!(42)!}

= 1.58200242 × 10¹⁰

Now, to find the  probability that you are holding three kings and four 6's from the deck, the remaining cards not kings or 6's :

we will need to divide the number of ways we can select three kings and four 6's from the deck by the no of ways we can select 10 cards out of the pack of 52 cards.

Mathematically; we have,

=\dfrac{52976}{1.58200242 \times 10^{10}}

= \mathbf{3.34866744 \times 10^{-6}}

4 0
4 years ago
Which ordered pair is a solution to the system of equations use the graph.
Jobisdone [24]

Answer:

(3,0)

Step-by-step explanation:

The <u>solution</u> of a system of equations is <u>where they meet on a graph.</u>

The two order pairs meet at (3,0)

4 0
4 years ago
Circle O shown below has a radius of 21 inches. Find, to the nearest tenth, the radian
lord [1]

Answer:

He's right it's 0.8 I got the answer right thanks a lot dude

8 0
3 years ago
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